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Rang	Thema	Aufgabe	Formatierte Aufgabe
2901	x 구하기	logarithmische Basis 6 von x+31- logarithmische Basis 6 von x-4=2	$\log_{6} (x + 31) - \log_{6} (x - 4) = 2$
2902	x 구하기	logarithmische Basis 6 von x+ logarithmische Basis 6 von x-3=2	$\log_{6} (x) + \log_{6} (x - 3) = 2$
2903	x 구하기	logarithmische Basis 5 von x+4+ logarithmische Basis 5 von 8 = logarithmische Basis 5 von 64	$\log_{5} (x + 4) + \log_{5} (8) = \log_{5} (64)$
2904	x 구하기	logarithmische Basis 6 von x^2+5 = logarithmische Basis 6 von 41	$\log_{6} (x^{2} + 5) = \log_{6} (41)$
2905	x 구하기	logarithmische Basis 3 von 2x-1- logarithmische Basis 3 von x-4=2	$\log_{3} (2 x - 1) - \log_{3} (x - 4) = 2$
2906	x 구하기	Logarithmische Basis 3 von 7x=2	$\log_{3} (7 x) = 2$
2907	x 구하기	Logarithmische Basis 20 von x^2-x=1	$\log_{20} (x^{2} - x) = 1$
2908	x 구하기	Logarithmische Basis 3 von x^2-4x-36=2	$\log_{3} (x^{2} - 4 x - 36) = 2$
2909	x 구하기	logarithmische Basis 3 von x-2 = logarithmische Basis 3 von x+6+2	$\log_{3} (x - 2) = \log_{3} (x + 6) + 2$
2910	x 구하기	logarithmische Basis 3 von x+19- logarithmische Basis 3 von x-7=3	$\log_{3} (x + 19) - \log_{3} (x - 7) = 3$
2911	x 구하기	logarithmische Basis 3 von x+1+ logarithmische Basis 3 von x-5=3	$\log_{3} (x + 1) + \log_{3} (x - 5) = 3$
2912	x 구하기	x^3+1331=0	$x^{3} + 1331 = 0$
2913	x 구하기	logarithmische Basis 3 von x=2- logarithmische Basis 3 von x-8	$\log_{3} (x) = 2 - \log_{3} (x - 8)$
2914	x 구하기	logarithmische Basis 5 von 4x+12- logarithmische Basis 5 von x-13=3	$\log_{5} (4 x + 12) - \log_{5} (x - 13) = 3$
2915	x 구하기	logarithmische Basis 5 von x+ logarithmische Basis 3 von x=1	$\log_{5} (x) + \log_{3} (x) = 1$
2916	x 구하기	logarithmische Basis 4 von x^2+3x- logarithmische Basis 4 von x+5=1	$\log_{4} (x^{2} + 3 x) - \log_{4} (x + 5) = 1$
2917	x 구하기	logarithmische Basis 4 von 8x- logarithmische Basis 4 von x-1=2	$\log_{4} (8 x) - \log_{4} (x - 1) = 2$
2918	x 구하기	logarithmische Basis 2 von x-1- logarithmische Basis 2 von x+3 = logarithmische Basis 2 von 1/x	$\log_{2} (x - 1) - \log_{2} (x + 3) = \log_{2} (\frac{1}{x})$
2919	x 구하기	Logarithmische Basis 2 von x-3=-2	$\log_{2} (x - 3) = - 2$
2920	x 구하기	logarithmische Basis 2 von x+1- logarithmische Basis 4 von x=1	$\log_{2} (x + 1) - \log_{4} (x) = 1$
2921	x 구하기	logarithmische Basis 2 von x+14- logarithmische Basis 2 von x-3=1	$\log_{2} (x + 14) - \log_{2} (x - 3) = 1$
2922	x 구하기	logarithmische Basis 2 von 8x- logarithmische Basis 2 von x^2-1 = logarithmische Basis 2 von 3	$\log_{2} (8 x) - \log_{2} (x^{2} - 1) = \log_{2} (3)$
2923	x 구하기	logarithmische Basis 16 von x+ logarithmische Basis 4 von x+ logarithmische Basis 2 von x=21	$\log_{16} (x) + \log_{4} (x) + \log_{2} (x) = 21$
2924	x 구하기	Logarithmische Basis 2 von x^2-4x-24=3	$\log_{2} (x^{2} - 4 x - 24) = 3$
2925	x 구하기	Logarithmische Basis 2 von x^2-4x-28=2	$\log_{2} (x^{2} - 4 x - 28) = 2$
2926	x 구하기	Logarithmische Basis 16 von x=-1/2	$\log_{16} (x) = - \frac{1}{2}$
2927	x 구하기	logarithmische Basis 16 von x-4+ logarithmische Basis 16 von x+2=1	$\log_{16} (x - 4) + \log_{16} (x + 2) = 1$
2928	x 구하기	logarithmische Basis 14 von x+49- logarithmische Basis 196 von x=1	$\log_{14} (x + 49) - \log_{196} (x) = 1$
2929	x 구하기	e^(x+3)=7	$e^{x + 3} = 7$
2930	x 구하기	e^(x-1)=(1/(e^2))^(x+5)	$e^{x - 1} = {(\frac{1}{e^{2}})}^{x + 5}$
2931	x 구하기	5e^(0.2x)=7	$5 e^{0.2 x} = 7$
2932	x 구하기	5e^(0.5x)=12	$5 e^{0.5 x} = 12$
2933	x 구하기	5(2^x)=6	$5 (2^{x}) = 6$
2934	x 구하기	5*18^(6x)=26	$5 \cdot 18^{6 x} = 26$
2935	x 구하기	5+yi=x+3i	$5 + y i = x + 3 i$
2936	x 구하기	4(x+h)=4(x+h^2+2+h)	$4 (x + h) = 4 (x + h^{2} + 2 + h)$
2937	x 구하기	3x-19=0	$3 x - 19 = 0$
2938	x 구하기	3500=700*2^(8x)	$3500 = 700 \cdot 2^{8 x}$
2939	x 구하기	3 natürlicher Logarithmus von x-3=1	$3 \ln (x - 3) = 1$
2940	x 구하기	3cos(x)-2=0	$3 \cos (x) - 2 = 0$
2941	x 구하기	3 Logarithmus von 3-x=1-x	$3 \log (3 - x) = 1 - x$
2942	x 구하기	4 Quadratwurzel von x-3=0	$4 \sqrt{x} - 3 = 0$
2943	x 구하기	4 logarithmische Basis 3 von x=28	$4 \log_{3} (x) = 28$
2944	x 구하기	4e^(7x)=10273	$4 e^{7 x} = 10273$
2945	x 구하기	4 = Quadratwurzel von -6-2x+ Quadratwurzel von 31-3x	$4 = \sqrt{- 6 - 2 x} + \sqrt{31 - 3 x}$
2946	X 구하기	4 natürlicher Logarithmus von 3X=15	$4 \ln (3 X) = 15$
2947	x 구하기	4 natürlicher Logarithmus von 3x=16	$4 \ln (3 x) = 16$
2948	x 구하기	27=x^(3/2)	$27 = x^{\frac{3}{2}}$
2949	x 구하기	27=3^(5x)*9^(x^2)	$27 = 3^{5 x} \cdot 9^{x^{2}}$
2950	x 구하기	Quadratwurzel von 2 Quadratwurzel von 2x+3 = Quadratwurzel von x+3	$\sqrt{2 \sqrt{2 x + 3}} = \sqrt{x + 3}$
2951	x 구하기	2cos(x+ Quadratwurzel von 3)=0	$2 \cos (x + \sqrt{3}) = 0$
2952	x 구하기	(x-7)^2=(x+3)^2	${(x - 7)}^{2} = {(x + 3)}^{2}$
2953	x 구하기	2cos(3x)=1	$2 \cos (3 x) = 1$
2954	x 구하기	-2sin(x)=-sin(x)cos(x)	$- 2 \sin (x) = - \sin (x) \cos (x)$
2955	x 구하기	2 natürlicher Logarithmus von x=7	$2 \ln (x) = 7$
2956	x 구하기	2 natürlicher Logarithmus von x = natürlicher Logarithmus von 3+ natürlicher Logarithmus von x+6	$2 \ln (x) = \ln (3) + \ln (x + 6)$
2957	x 구하기	2 natürlicher Logarithmus von x+2=6	$2 \ln (x + 2) = 6$
2958	x 구하기	200=50e^(3x)	$200 = 50 e^{3 x}$
2959	x 구하기	2+13sin(x)=14cos(x)^2	$2 + 13 \sin (x) = 14 \cos^{2} (x)$
2960	x 구하기	2x^2+5x=8	$2 x^{2} + 5 x = 8$
2961	x 구하기	2x^2-x-21=0	$2 x^{2} - x - 21 = 0$
2962	x 구하기	2+3 natürlicher Logarithmus von x=12	$2 + 3 \ln (x) = 12$
2963	x 구하기	3sin(x)^2-8sin(x)-3=0	$3 \sin^{2} (x) - 8 \sin (x) - 3 = 0$
2964	x 구하기	3x^(1/2)+5x^(1/4)-2=0	$3 x^{\frac{1}{2}} + 5 x^{\frac{1}{4}} - 2 = 0$
2965	x 구하기	3(2^x)=6	$3 (2^{x}) = 6$
2966	x 구하기	2x natürlicher Logarithmus von 1/x-x=0	$2 x \ln (\frac{1}{x}) - x = 0$
2967	x 구하기	2x natürlicher Logarithmus von x+x=0	$2 x \ln (x) + x = 0$
2968	x 구하기	2x-3=4x-5	$2 x - 3 = 4 x - 5$
2969	x 구하기	2x+1=5/(x+2)	$2 x + 1 = \frac{5}{x + 2}$
2970	x 구하기	3(x+1)=8(x-1)+5	$3 (x + 1) = 8 (x - 1) + 5$
2971	x 구하기	3(3x-1)^2=21	$3 {(3 x - 1)}^{2} = 21$
2972	x 구하기	-2 logarithmische Basis 4 von x = logarithmische Basis 4 von 9	$- 2 \log_{4} (x) = \log_{4} (9)$
2973	x 구하기	2 logarithmische Basis 3 von x+4 = logarithmische Basis 3 von 9+2	$2 \log_{3} (x + 4) = \log_{3} (9) + 2$
2974	x 구하기	2e^(2x)-7e^x+3=0	$2 e^{2 x} - 7 e^{x} + 3 = 0$
2975	x 구하기	2e^x+e^x-15=0	$2 e^{x} + e^{x} - 15 = 0$
2976	x 구하기	2e^(2x)+5e^x-3=0	$2 e^{2 x} + 5 e^{x} - 3 = 0$
2977	x 구하기	2(6+6x)+2x=288	$2 (6 + 6 x) + 2 x = 288$
2978	x 구하기	14+20 natürlicher Logarithmus von 7x=54	$14 + 20 \ln (7 x) = 54$
2979	x 구하기	2-1/(x+1)=1/(x^2+x)	$2 - \frac{1}{x + 1} = \frac{1}{x^{2} + x}$
2980	x 구하기	2arccos(x)=pi	$2 \arccos (x) = π$
2981	x 구하기	2 logarithmische Basis 5 von x = logarithmische Basis 5 von 2+ logarithmische Basis 5 von 4+10	$2 \log_{5} (x) = \log_{5} (2) + \log_{5} (4 + 10)$
2982	x 구하기	16^x-7*4^x+6=0	$16^{x} - 7 \cdot 4^{x} + 6 = 0$
2983	x 구하기	2 logarithmische Basis 4 von x+4- logarithmische Basis 4 von x+12=1	$2 \log_{4} (x + 4) - \log_{4} (x + 12) = 1$
2984	x 구하기	2sin(x)^2+13sin(x)+6=0	$2 \sin^{2} (x) + 13 \sin (x) + 6 = 0$
2985	x 구하기	2x^2e^(2x)+2xe^(2x)=0	$2 x^{2} e^{2 x} + 2 x e^{2 x} = 0$
2986	x 구하기	2 Quadratwurzel von x+4=x+1	$2 \sqrt{x + 4} = x + 1$
2987	x 구하기	2sin(x)^2-7sin(x)-4=0	$2 \sin^{2} (x) - 7 \sin (x) - 4 = 0$
2988	x 구하기	Quadratwurzel von 5x+24=x	$\sqrt{5 x + 24} = x$
2989	x 구하기	15=5^(x+3)-7	$15 = 5^{x + 3} - 7$
2990	x 구하기	11x^3+15x^2-25x+7=0	$11 x^{3} + 15 x^{2} - 25 x + 7 = 0$
2991	x 구하기	1500(1.2)^x=3000	$1500 {(1.2)}^{x} = 3000$
2992	x 구하기	16cos(x)^2=4	$16 \cos^{2} (x) = 4$
2993	x 구하기	17=3^x	$17 = 3^{x}$
2994	x 구하기	150=50e^(7x)	$150 = 50 e^{7 x}$
2995	x 구하기	2(12^x)=190	$2 (12^{x}) = 190$
2996	x 구하기	2*10^(2-x)=13	$2 \cdot 10^{2 - x} = 13$
2997	x 구하기	1000=500e^(2x)	$1000 = 500 e^{2 x}$
2998	x 구하기	1000e^(-4x)=2400	$1000 e^{- 4 x} = 2400$
2999	x 구하기	0=2sin(x)cos(x)+cos(x)	$0 = 2 \sin (x) \cos (x) + \cos (x)$
3000	x 구하기	xe^x+e^x=0	$x e^{x} + e^{x} = 0$