Mathway | Problemas populares

Problemas populares

Calificar	Tema	Problema	Problema formateado
3701	Hallar los porcentajes de masa	AgSnPb	$A g S n P b$
3702	Hallar los porcentajes de masa	B_2H_6	$B_{2} H_{6}$
3703	Hallar los porcentajes de masa	Ba(OH)_2	$B a {(O H)}_{2}$
3704	Hallar los porcentajes de masa	BaNO_3	$B a N O_{3}$
3705	Balancear	Cu_2CO_3+NaCN→Na_2CO_3+CuCN	$C u_{2} C O_{3} + N a C N \to N a_{2} C O_{3} + C u C N$
3706	Balancear	CuCl_2+H_2S→CuS_2+Cl_2H_2	$C u C l_{2} + H_{2} S \to C u S_{2} + C l_{2} H_{2}$
3707	Balancear	d=30m	$d = 30 m$
3708	Balancear	Cr(NO_3)_3+Al→Al(NO_3)_3+Cr	$C r {(N O_{3})}_{3} + A l \to A l {(N O_{3})}_{3} + C r$
3709	Balancear	co_2→co	$c o_{2} \to c o$
3710	Balancear	CO+2H_2→CH_3OH	$C O + 2 H_{2} \to C H_{3} O H$
3711	Balancear	CH_4(g)+O_2(g)→CO(g)+H_2O(I)	$C H_{4} (g) + O_{2} (g) \to C O (g) + H_{2} O (I)$
3712	Balancear	CH_3COOH+O_2=CO_2+H_2O	$C H_{3} C O O H + O_{2} = C O_{2} + H_{2} O$
3713	Balancear	CH_3+O_2=CO_2+H_2O	$C H_{3} + O_{2} = C O_{2} + H_{2} O$
3714	Balancear	CH_4+Cl_2→HCl	$C H_{4} + C l_{2} \to H C l$
3715	Balancear	CH_4+CO_2→CO_2+H_2	$C H_{4} + C O_{2} \to C O_{2} + H_{2}$
3716	Balancear	Cl_2+MgBr_2→Br_2+MgCl_2	$C l_{2} + M g B r_{2} \to B r_{2} + M g C l_{2}$
3717	Balancear	Cl_2O_7+H_2O=HClO_4	$C l_{2} O_{7} + H_{2} O = H C l O_{4}$
3718	Balancear	Cl_5Re_2→V	$C l_{5} R e_{2} \to V$
3719	Balancear	Co_2+2LiOH=Li_2CO_3+H_2O	$C o_{2} + 2 L i O H = L i_{2} C O_{3} + H_{2} O$
3720	Balancear	CO_2+H_2O→C_2+H_12+O_6+O_2	$C O_{2} + H_{2} O \to C_{2} + H_{12} + O_{6} + O_{2}$
3721	Balancear	CaF_2+Li_2SO_4→CaSO_4+LiFS	$C a F_{2} + L i_{2} S O_{4} \to C a S O_{4} + L i F S$
3722	Balancear	CaO+CO_2→(CaCO_3)	$C a O + C O_{2} \to (C a C O_{3})$
3723	Balancear	CaO+H+PO_4→Ca+PO_4+HOH	$C a O + H + P O_{4} \to C a + P O_{4} + H O H$
3724	Balancear	CaSiO_3+HF→H_2O+SiF_4+CaF_2	$C a S i O_{3} + H F \to H_{2} O + S i F_{4} + C a F_{2}$
3725	Balancear	CaSO_4+HCl→CaCl+HSO_4	$C a S O_{4} + H C l \to C a C l + H S O_{4}$
3726	Balancear	C→O	$C \to O$
3727	Balancear	Ca(NO_3)_2+Na_3PO_4=Ca_3(PO_4)_2+NaNO_3	$C a {(N O_{3})}_{2} + N a_{3} P O_{4} = C a_{3} {(P O_{4})}_{2} + N a N O_{3}$
3728	Balancear	Ca(OH)_2+H_3PO_4→Ca_3(PO_4)_2+H(2O)	$C a {(O H)}_{2} + H_{3} P O_{4} \to C a_{3} {(P O_{4})}_{2} + H (2 O)$
3729	Balancear	Ca_3(PO_4)_2+H_3PO_4→Ca(H_2PO_4)_2	$C a_{3} {(P O_{4})}_{2} + H_{3} P O_{4} \to C a {(H_{2} P O_{4})}_{2}$
3730	Balancear	Ca+2Li→LiCa	$C a + 2 L i \to L i C a$
3731	Balancear	Ca+5Tc=4Os	$C a + 5 T c = 4 O s$
3732	Balancear	Ca→K	$C a \to K$
3733	Simplificar	NH_3+O_2 xH_2O+HNO_2+HNO_3	$N H_{3} + O_{2} x H_{2} O + H N O_{2} + H N O_{3}$
3734	Balancear	CaCl_2+AgNO_3→AgCl+Ca(NO_3)_2	$C a C l_{2} + A g N O_{3} \to A g C l + C a {(N O_{3})}_{2}$
3735	Balancear	C+2H_2→CH_4	$C + 2 H_{2} \to C H_{4}$
3736	Balancear	C+2O→CO	$C + 2 O \to C O$
3737	Balancear	C+CO_2=2CO	$C + C O_{2} = 2 C O$
3738	Balancear	C+KOH=CO_2+K	$C + K O H = C O_{2} + K$
3739	Balancear	C_3H_6(g)+O_2(g)→CO_2(g)+H_2O(g)	$C_{3} H_{6} (g) + O_{2} (g) \to C O_{2} (g) + H_{2} O (g)$
3740	Balancear	C_4H_10(g)+O_2(g)→CO_2+H_2O(l)	$C_{4} H_{10} (g) + O_{2} (g) \to C O_{2} + H_{2} O (l)$
3741	Balancear	C_4H_6O_3+H_2O→C_2H_4O_2	$C_{4} H_{6} O_{3} + H_{2} O \to C_{2} H_{4} O_{2}$
3742	Balancear	C_4H_8+O_2→CO_2+H_2O	$C_{4} H_{8} + O_{2} \to C O_{2} + H_{2} O$
3743	Balancear	C_6H_5CO_1OH+O_2=CO_2H_2*0	$C_{6} H_{5} C O_{1} O H + O_{2} = C O_{2} H_{2} \cdot 0$
3744	Balancear	C_6H_6+Br_2→C_6H_5Br+HBr	$C_{6} H_{6} + B r_{2} \to C_{6} H_{5} B r + H B r$
3745	Balancear	HNO_3+LiOH→LiNO_3+HOH	$H N O_{3} + L i O H \to L i N O_{3} + H O H$
3746	Balancear	HNO_3=H_3PO_4	$H N O_{3} = H_{3} P O_{4}$
3747	Balancear	HO+K→KOH	$H O + K \to K O H$
3748	Balancear	K_2Cr_2O_7+SnCl_2+HCl→CrCl_3+SnCl_4+KCl+H_2O	$K_{2} C r_{2} O_{7} + S n C l_{2} + H C l \to C r C l_{3} + S n C l_{4} + K C l + H_{2} O$
3749	Balancear	K_2PtCl_4+NH_3→Pt(NH_3)_2Cl_2+KCl	$K_{2} P t C l_{4} + N H_{3} \to P t {(N H_{3})}_{2} C l_{2} + K C l$
3750	Balancear	K_2S+CuCl_2→CuS+KCl	$K_{2} S + C u C l_{2} \to C u S + K C l$
3751	Balancear	K_3PO_4+Ca(NO_3)_2→Ca_3(PO_4)_2+KNO_3	$K_{3} P O_{4} + C a {(N O_{3})}_{2} \to C a_{3} {(P O_{4})}_{2} + K N O_{3}$
3752	Balancear	K_3PO_4+MgCl→KCl+Mg_3(PO_4)_2	$K_{3} P O_{4} + M g C l \to K C l + M g_{3} {(P O_{4})}_{2}$
3753	Balancear	K+B_2O_3=K_2O+B	$K + B_{2} O_{3} = K_{2} O + B$
3754	Balancear	K+Br_2→KBr	$K + B r_{2} \to K B r$
3755	حل من أجل v	760v=350.082*769	$760 \cdot v = 35 \cdot 0.082 \cdot 769$
3756	Balancear	K+Br_9→KBr	$K + B r_{9} \to K B r$
3757	حل من أجل w	9+w=-1	$9 + w = - 1$
3758	Balancear	K_2CO_3+SiO_2=K_2SiO_3+CO_2	$K_{2} C O_{3} + S i O_{2} = K_{2} S i O_{3} + C O_{2}$
3759	Balancear	KCI(s)→h_2o	$K C I (s) \to h_{2} o$
3760	حل من أجل x	(40-2x)*(55-2x)=1350	$(40 - 2 x) \cdot (55 - 2 x) = 1350$
3761	Balancear	H_2SO_4+KOH→KSO_4+H_2O	$H_{2} S O_{4} + K O H \to K S O_{4} + H_{2} O$
3762	حل من أجل x	(x-1)=16	$(x - 1) = 16$
3763	حل من أجل x	0.02(10)=(0.140)x	$0.02 (10) = (0.14) x$
3764	Balancear	H_2SO_4+Al(OH)_3=3H_2O+Al(SO_4H)_3	$H_{2} S O_{4} + A l {(O H)}_{3} = 3 H_{2} O + A l {(S O_{4} H)}_{3}$
3765	حل من أجل x	-4x-33=19	$- 4 x - 33 = 19$
3766	Balancear	H_2S+Cr(OH)_3→CrS+HOH	$H_{2} S + C r {(O H)}_{3} \to C r S + H O H$
3767	Balancear	HA+BOH→H_2O+BA	$H A + B O H \to H_{2} O + B A$
3768	Balancear	HCl+Al(OH)_3→H_2O+AlCl_3	$H C l + A l {(O H)}_{3} \to H_{2} O + A l C l_{3}$
3769	Balancear	HCl+Ba(OH)_2→BaCl+H(OH)_2	$H C l + B a {(O H)}_{2} \to B a C l + H {(O H)}_{2}$
3770	Balancear	HCL+MNO_2=MNCL_2+CL_2+H_2O	$H C L + M N O_{2} = M N C L_{2} + C L_{2} + H_{2} O$
3771	Balancear	HCl+N→NH_4Cl	$H C l + N \to N H_{4} C l$
3772	Balancear	HCl+Na_2S_2O_3→SO_2+S+H_2O+NaCl	$H C l + N a_{2} S_{2} O_{3} \to S O_{2} + S + H_{2} O + N a C l$
3773	Balancear	HClO_3+H_2O→HClO+H_2O	$H C l O_{3} + H_{2} O \to H C l O + H_{2} O$
3774	Balancear	HF+KOH→KF+H_2O	$H F + K O H \to K F + H_{2} O$
3775	Balancear	Hg(NO_3)_2+KI→KNO_3+HgI_2	$H g {(N O_{3})}_{2} + K I \to K N O_{3} + H g I_{2}$
3776	Balancear	HMnO_4+AsH_3+H_2SO_4→H_3AsO_4+MnSO_4+H_2O	$H M n O_{4} + A s H_{3} + H_{2} S O_{4} \to H_{3} A s O_{4} + M n S O_{4} + H_{2} O$
3777	Balancear	H_2O+O_4=O_3	$H_{2} O + O_{4} = O_{3}$
3778	Balancear	H_2+N_2=2NH_3	$H_{2} + N_{2} = 2 N H_{3}$
3779	Balancear	H_2+O_2→h_2*0	$H_{2} + O_{2} \to h_{2} \cdot 0$
3780	Balancear	H_2+O_2→H_2O_2	$H_{2} + O_{2} \to H_{2} O_{2}$
3781	Balancear	H_2→HeNi	$H_{2} \to H e N i$
3782	Balancear	FeS+O_2=Fe_2O_3+SO_2	$F e S + O_{2} = F e_{2} O_{3} + S O_{2}$
3783	Balancear	GaF_3+Cs→CsF+Ga	$G a F_{3} + C s \to C s F + G a$
3784	Balancear	H(2(g))+O(2(g))→H(2O)	$H (2 (g)) + O (2 (g)) \to H (2 O)$
3785	Balancear	Fe+H_2SO_4→Fe(SO_4)_3+SO_2+H_2O	$F e + H_{2} S O_{4} \to F e {(S O_{4})}_{3} + S O_{2} + H_{2} O$
3786	Balancear	Fe+O_2=FeO	$F e + O_{2} = F e O$
3787	Balancear	FeCl_2+H_2O_2+HCl→FeCl_3+H_2O	$F e C l_{2} + H_{2} O_{2} + H C l \to F e C l_{3} + H_{2} O$
3788	Balancear	Fe(OH)_3→Fe_2O_3+H_2O	$F e {(O H)}_{3} \to F e_{2} O_{3} + H_{2} O$
3789	Balancear	Fe_2O_3+3CO=2Fe+3CO_2	$F e_{2} O_{3} + 3 C O = 2 F e + 3 C O_{2}$
3790	Balancear	Fe_2O+CO→Fe+CO_2	$F e_{2} O + C O \to F e + C O_{2}$
3791	Balancear	Fe_3O_4+CO→Fe+CO_2	$F e_{3} O_{4} + C O \to F e + C O_{2}$
3792	Balancear	Al_4C_3+H_2O→Al(OH)_3+CH_4	$A l_{4} C_{3} + H_{2} O \to A l {(O H)}_{3} + C H_{4}$
3793	Balancear	Al+Cl=AlCl_3	$A l + C l = A l C l_{3}$
3794	Balancear	Al+Cu(NO_3)_2→Cu+Al(NO_3)_3	$A l + C u {(N O_{3})}_{2} \to C u + A l {(N O_{3})}_{3}$
3795	Balancear	Al+CuCl_2→CuAl+Cl_2	$A l + C u C l_{2} \to C u A l + C l_{2}$
3796	Balancear	AgNO_3aq+K_2CO_3→Ag_2CO_3+2KNO_3	$A g N O_{3} a q + K_{2} C O_{3} \to A g_{2} C O_{3} + 2 K N O_{3}$
3797	Balancear	Al(H_2PO_4)_3+H_2SO_4→Al(SO_4)_3+H_3PO_4	$A l {(H_{2} P O_{4})}_{3} + H_{2} S O_{4} \to A l {(S O_{4})}_{3} + H_{3} P O_{4}$
3798	Balancear	Al_2O_3+6HCl=3H_2O+AlCl_3	$A l_{2} O_{3} + 6 H C l = 3 H_{2} O + A l C l_{3}$
3799	Balancear	Al_2O_3+HCl=AlCl_3+H_2O	$A l_{2} O_{3} + H C l = A l C l_{3} + H_{2} O$
3800	Balancear	Ag_2S+HNO_3→Ag_2SO_4+NO_2	$A g_{2} S + H N O_{3} \to A g_{2} S O_{4} + N O_{2}$