代数示例

⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 0 & 3 & 0 & 1 4 & 3 & 0 & 3 1 & 2 & 2 & 4 1 & 2 & 3 & 4 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 0 & 3 & 0 & 1 \\ 4 & 3 & 0 & 3 \\ 1 & 2 & 2 & 4 \\ 1 & 2 & 3 & 4 \end{array}]$

解题步骤 1

Choose the row or column with the most

$0$ elements. If there are no

$0$ elements choose any row or column. Multiply every element in row

$1$ by its cofactor and add.

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解题步骤 1.1

Consider the corresponding sign chart.

$| \begin{array}{c} + & - & + & - \\ - & + & - & + \\ + & - & + & - \\ - & + & - & + \end{array} |$

解题步骤 1.2

The cofactor is the minor with the sign changed if the indices match a

$-$ position on the sign chart.

解题步骤 1.3

The minor for

$a_{11}$ is the determinant with row

$1$ and column

$1$ deleted.

$| \begin{array}{c} 3 & 0 & 3 \\ 2 & 2 & 4 \\ 2 & 3 & 4 \end{array} |$

解题步骤 1.4

Multiply element

$a_{11}$ by its cofactor.

$0 | \begin{array}{c} 3 & 0 & 3 \\ 2 & 2 & 4 \\ 2 & 3 & 4 \end{array} |$

解题步骤 1.5

The minor for

$a_{12}$ is the determinant with row

$1$ and column

$2$ deleted.

$| \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} |$

解题步骤 1.6

Multiply element

$a_{12}$ by its cofactor.

$- 3 | \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} |$

解题步骤 1.7

The minor for

$a_{13}$ is the determinant with row

$1$ and column

$3$ deleted.

$| \begin{array}{c} 4 & 3 & 3 \\ 1 & 2 & 4 \\ 1 & 2 & 4 \end{array} |$

解题步骤 1.8

Multiply element

$a_{13}$ by its cofactor.

$0 | \begin{array}{c} 4 & 3 & 3 \\ 1 & 2 & 4 \\ 1 & 2 & 4 \end{array} |$

解题步骤 1.9

The minor for

$a_{14}$ is the determinant with row

$1$ and column

$4$ deleted.

$| \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 1.10

Multiply element

$a_{14}$ by its cofactor.

$- 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 1.11

Add the terms together.

$0 | \begin{array}{c} 3 & 0 & 3 \\ 2 & 2 & 4 \\ 2 & 3 & 4 \end{array} | - 3 | \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} | + 0 | \begin{array}{c} 4 & 3 & 3 \\ 1 & 2 & 4 \\ 1 & 2 & 4 \end{array} | - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 2

将

$0$ 乘以

$| \begin{array}{c} 3 & 0 & 3 \\ 2 & 2 & 4 \\ 2 & 3 & 4 \end{array} |$ 。

$0 - 3 | \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} | + 0 | \begin{array}{c} 4 & 3 & 3 \\ 1 & 2 & 4 \\ 1 & 2 & 4 \end{array} | - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 3

将

$0$ 乘以

$| \begin{array}{c} 4 & 3 & 3 \\ 1 & 2 & 4 \\ 1 & 2 & 4 \end{array} |$ 。

$0 - 3 | \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} | + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4

计算

$| \begin{array}{c} 4 & 0 & 3 \\ 1 & 2 & 4 \\ 1 & 3 & 4 \end{array} |$ 。

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解题步骤 4.1

Choose the row or column with the most

$0$ elements. If there are no

$0$ elements choose any row or column. Multiply every element in row

$1$ by its cofactor and add.

点击获取更多步骤...

解题步骤 4.1.1

Consider the corresponding sign chart.

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

解题步骤 4.1.2

The cofactor is the minor with the sign changed if the indices match a

$-$ position on the sign chart.

解题步骤 4.1.3

The minor for

$a_{11}$ is the determinant with row

$1$ and column

$1$ deleted.

$| \begin{array}{c} 2 & 4 \\ 3 & 4 \end{array} |$

解题步骤 4.1.4

Multiply element

$a_{11}$ by its cofactor.

$4 | \begin{array}{c} 2 & 4 \\ 3 & 4 \end{array} |$

解题步骤 4.1.5

The minor for

$a_{12}$ is the determinant with row

$1$ and column

$2$ deleted.

$| \begin{array}{c} 1 & 4 \\ 1 & 4 \end{array} |$

解题步骤 4.1.6

Multiply element

$a_{12}$ by its cofactor.

$0 | \begin{array}{c} 1 & 4 \\ 1 & 4 \end{array} |$

解题步骤 4.1.7

The minor for

$a_{13}$ is the determinant with row

$1$ and column

$3$ deleted.

$| \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$

解题步骤 4.1.8

Multiply element

$a_{13}$ by its cofactor.

$3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$

解题步骤 4.1.9

Add the terms together.

$0 - 3 (4 | \begin{array}{c} 2 & 4 \\ 3 & 4 \end{array} | + 0 | \begin{array}{c} 1 & 4 \\ 1 & 4 \end{array} | + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.2

将

$0$ 乘以

$| \begin{array}{c} 1 & 4 \\ 1 & 4 \end{array} |$ 。

$0 - 3 (4 | \begin{array}{c} 2 & 4 \\ 3 & 4 \end{array} | + 0 + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.3

计算

$| \begin{array}{c} 2 & 4 \\ 3 & 4 \end{array} |$ 。

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解题步骤 4.3.1

可以使用公式

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 求

$2 \times 2$ 矩阵的行列式。

$0 - 3 (4 (2 \cdot 4 - 3 \cdot 4) + 0 + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.3.2

化简行列式。

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解题步骤 4.3.2.1

化简每一项。

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解题步骤 4.3.2.1.1

将

$2$ 乘以

$4$ 。

$0 - 3 (4 (8 - 3 \cdot 4) + 0 + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.3.2.1.2

将

$- 3$ 乘以

$4$ 。

$0 - 3 (4 (8 - 12) + 0 + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.3.2.2

从

$8$ 中减去

$12$ 。

$0 - 3 (4 \cdot - 4 + 0 + 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.4

计算

$| \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$ 。

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解题步骤 4.4.1

可以使用公式

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 求

$2 \times 2$ 矩阵的行列式。

$0 - 3 (4 \cdot - 4 + 0 + 3 (1 \cdot 3 - 1 \cdot 2)) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.4.2

化简行列式。

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解题步骤 4.4.2.1

化简每一项。

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解题步骤 4.4.2.1.1

将

$3$ 乘以

$1$ 。

$0 - 3 (4 \cdot - 4 + 0 + 3 (3 - 1 \cdot 2)) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.4.2.1.2

将

$- 1$ 乘以

$2$ 。

$0 - 3 (4 \cdot - 4 + 0 + 3 (3 - 2)) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.4.2.2

从

$3$ 中减去

$2$ 。

$0 - 3 (4 \cdot - 4 + 0 + 3 \cdot 1) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.5

化简行列式。

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解题步骤 4.5.1

化简每一项。

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解题步骤 4.5.1.1

将

$4$ 乘以

$- 4$ 。

$0 - 3 (- 16 + 0 + 3 \cdot 1) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.5.1.2

将

$3$ 乘以

$1$ 。

$0 - 3 (- 16 + 0 + 3) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.5.2

将

$- 16$ 和

$0$ 相加。

$0 - 3 (- 16 + 3) + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 4.5.3

将

$- 16$ 和

$3$ 相加。

$0 - 3 \cdot - 13 + 0 - 1 | \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$

解题步骤 5

计算

$| \begin{array}{c} 4 & 3 & 0 \\ 1 & 2 & 2 \\ 1 & 2 & 3 \end{array} |$ 。

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解题步骤 5.1

Choose the row or column with the most

$0$ elements. If there are no

$0$ elements choose any row or column. Multiply every element in row

$1$ by its cofactor and add.

点击获取更多步骤...

解题步骤 5.1.1

Consider the corresponding sign chart.

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

解题步骤 5.1.2

The cofactor is the minor with the sign changed if the indices match a

$-$ position on the sign chart.

解题步骤 5.1.3

The minor for

$a_{11}$ is the determinant with row

$1$ and column

$1$ deleted.

$| \begin{array}{c} 2 & 2 \\ 2 & 3 \end{array} |$

解题步骤 5.1.4

Multiply element

$a_{11}$ by its cofactor.

$4 | \begin{array}{c} 2 & 2 \\ 2 & 3 \end{array} |$

解题步骤 5.1.5

The minor for

$a_{12}$ is the determinant with row

$1$ and column

$2$ deleted.

$| \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$

解题步骤 5.1.6

Multiply element

$a_{12}$ by its cofactor.

$- 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$

解题步骤 5.1.7

The minor for

$a_{13}$ is the determinant with row

$1$ and column

$3$ deleted.

$| \begin{array}{c} 1 & 2 \\ 1 & 2 \end{array} |$

解题步骤 5.1.8

Multiply element

$a_{13}$ by its cofactor.

$0 | \begin{array}{c} 1 & 2 \\ 1 & 2 \end{array} |$

解题步骤 5.1.9

Add the terms together.

$0 - 3 \cdot - 13 + 0 - 1 (4 | \begin{array}{c} 2 & 2 \\ 2 & 3 \end{array} | - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0 | \begin{array}{c} 1 & 2 \\ 1 & 2 \end{array} |)$

解题步骤 5.2

将

$0$ 乘以

$| \begin{array}{c} 1 & 2 \\ 1 & 2 \end{array} |$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 | \begin{array}{c} 2 & 2 \\ 2 & 3 \end{array} | - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0)$

解题步骤 5.3

计算

$| \begin{array}{c} 2 & 2 \\ 2 & 3 \end{array} |$ 。

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解题步骤 5.3.1

可以使用公式

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 求

$2 \times 2$ 矩阵的行列式。

$0 - 3 \cdot - 13 + 0 - 1 (4 (2 \cdot 3 - 2 \cdot 2) - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0)$

解题步骤 5.3.2

化简行列式。

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解题步骤 5.3.2.1

化简每一项。

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解题步骤 5.3.2.1.1

将

$2$ 乘以

$3$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 (6 - 2 \cdot 2) - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0)$

解题步骤 5.3.2.1.2

将

$- 2$ 乘以

$2$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 (6 - 4) - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0)$

解题步骤 5.3.2.2

从

$6$ 中减去

$4$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 \cdot 2 - 3 | \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} | + 0)$

解题步骤 5.4

计算

$| \begin{array}{c} 1 & 2 \\ 1 & 3 \end{array} |$ 。

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解题步骤 5.4.1

可以使用公式

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 求

$2 \times 2$ 矩阵的行列式。

$0 - 3 \cdot - 13 + 0 - 1 (4 \cdot 2 - 3 (1 \cdot 3 - 1 \cdot 2) + 0)$

解题步骤 5.4.2

化简行列式。

点击获取更多步骤...

解题步骤 5.4.2.1

化简每一项。

点击获取更多步骤...

解题步骤 5.4.2.1.1

将

$3$ 乘以

$1$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 \cdot 2 - 3 (3 - 1 \cdot 2) + 0)$

解题步骤 5.4.2.1.2

将

$- 1$ 乘以

$2$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 \cdot 2 - 3 (3 - 2) + 0)$

解题步骤 5.4.2.2

从

$3$ 中减去

$2$ 。

$0 - 3 \cdot - 13 + 0 - 1 (4 \cdot 2 - 3 \cdot 1 + 0)$

解题步骤 5.5

化简行列式。

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解题步骤 5.5.1

化简每一项。

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解题步骤 5.5.1.1

将

$4$ 乘以

$2$ 。

$0 - 3 \cdot - 13 + 0 - 1 (8 - 3 \cdot 1 + 0)$

解题步骤 5.5.1.2

将

$- 3$ 乘以

$1$ 。

$0 - 3 \cdot - 13 + 0 - 1 (8 - 3 + 0)$

解题步骤 5.5.2

从

$8$ 中减去

$3$ 。

$0 - 3 \cdot - 13 + 0 - 1 (5 + 0)$

解题步骤 5.5.3

将

$5$ 和

$0$ 相加。

$0 - 3 \cdot - 13 + 0 - 1 \cdot 5$

解题步骤 6

化简行列式。

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解题步骤 6.1

化简每一项。

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解题步骤 6.1.1

将

$- 3$ 乘以

$- 13$ 。

$0 + 39 + 0 - 1 \cdot 5$

解题步骤 6.1.2

将

$- 1$ 乘以

$5$ 。

$0 + 39 + 0 - 5$

解题步骤 6.2

将

$0$ 和

$39$ 相加。

$39 + 0 - 5$

解题步骤 6.3

将

$39$ 和

$0$ 相加。

$39 - 5$

解题步骤 6.4

从

$39$ 中减去

$5$ 。

$34$

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