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Algebra Examples
12+20x=1012+20x=10
Step 1
Step 1.1
Subtract 1212 from both sides of the equation.
20x=10-1220x=10−12
Step 1.2
Subtract 1212 from 1010.
20x=-220x=−2
20x=-220x=−2
Step 2
Step 2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
x,1x,1
Step 2.2
The LCM of one and any expression is the expression.
xx
xx
Step 3
Step 3.1
Multiply each term in 20x=-220x=−2 by xx.
20xx=-2x20xx=−2x
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of xx.
Step 3.2.1.1
Cancel the common factor.
20xx=-2x
Step 3.2.1.2
Rewrite the expression.
20=-2x
20=-2x
20=-2x
20=-2x
Step 4
Step 4.1
Rewrite the equation as -2x=20.
-2x=20
Step 4.2
Divide each term in -2x=20 by -2 and simplify.
Step 4.2.1
Divide each term in -2x=20 by -2.
-2x-2=20-2
Step 4.2.2
Simplify the left side.
Step 4.2.2.1
Cancel the common factor of -2.
Step 4.2.2.1.1
Cancel the common factor.
-2x-2=20-2
Step 4.2.2.1.2
Divide x by 1.
x=20-2
x=20-2
x=20-2
Step 4.2.3
Simplify the right side.
Step 4.2.3.1
Divide 20 by -2.
x=-10
x=-10
x=-10
x=-10