Algebra Examples

Find the Slope of a Perpendicular Line 5x-2y=7
5x-2y=7
Step 1
Rewrite in slope-intercept form.
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Step 1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 1.2
Subtract 5x from both sides of the equation.
-2y=7-5x
Step 1.3
Divide each term in -2y=7-5x by -2 and simplify.
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Step 1.3.1
Divide each term in -2y=7-5x by -2.
-2y-2=7-2+-5x-2
Step 1.3.2
Simplify the left side.
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Step 1.3.2.1
Cancel the common factor of -2.
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Step 1.3.2.1.1
Cancel the common factor.
-2y-2=7-2+-5x-2
Step 1.3.2.1.2
Divide y by 1.
y=7-2+-5x-2
y=7-2+-5x-2
y=7-2+-5x-2
Step 1.3.3
Simplify the right side.
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Step 1.3.3.1
Simplify each term.
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Step 1.3.3.1.1
Move the negative in front of the fraction.
y=-72+-5x-2
Step 1.3.3.1.2
Dividing two negative values results in a positive value.
y=-72+5x2
y=-72+5x2
y=-72+5x2
y=-72+5x2
Step 1.4
Write in y=mx+b form.
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Step 1.4.1
Reorder -72 and 5x2.
y=5x2-72
Step 1.4.2
Reorder terms.
y=52x-72
y=52x-72
y=52x-72
Step 2
Using the slope-intercept form, the slope is 52.
m=52
Step 3
The equation of a perpendicular line to y=52x-72 must have a slope that is the negative reciprocal of the original slope.
mperpendicular=-152
Step 4
Simplify the result.
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Step 4.1
Multiply the numerator by the reciprocal of the denominator.
mperpendicular=-(1(25))
Step 4.2
Multiply 25 by 1.
mperpendicular=-25
mperpendicular=-25
Step 5
 [x2  12  π  xdx ]