Algebra Examples

Solve Using the Square Root Property 2x^2-50=0
2x2-50=02x250=0
Step 1
Add 5050 to both sides of the equation.
2x2=502x2=50
Step 2
Divide each term in 2x2=502x2=50 by 22 and simplify.
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Step 2.1
Divide each term in 2x2=502x2=50 by 22.
2x22=5022x22=502
Step 2.2
Simplify the left side.
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Step 2.2.1
Cancel the common factor of 22.
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Step 2.2.1.1
Cancel the common factor.
2x22=502
Step 2.2.1.2
Divide x2 by 1.
x2=502
x2=502
x2=502
Step 2.3
Simplify the right side.
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Step 2.3.1
Divide 50 by 2.
x2=25
x2=25
x2=25
Step 3
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
x=±25
Step 4
Simplify ±25.
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Step 4.1
Rewrite 25 as 52.
x=±52
Step 4.2
Pull terms out from under the radical, assuming positive real numbers.
x=±5
x=±5
Step 5
The complete solution is the result of both the positive and negative portions of the solution.
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Step 5.1
First, use the positive value of the ± to find the first solution.
x=5
Step 5.2
Next, use the negative value of the ± to find the second solution.
x=-5
Step 5.3
The complete solution is the result of both the positive and negative portions of the solution.
x=5,-5
x=5,-5
 [x2  12  π  xdx ]