Algebra Examples

Find the Domain (fog)(x) , f(x)=1/(x+3) , g(x)=2/x
(fog)(x) , f(x)=1x+3 , g(x)=2x
Step 1
Set up the composite result function.
f(g(x))
Step 2
Evaluate f(2x) by substituting in the value of g into f.
f(2x)=1(2x)+3
Step 3
Set the denominator in 2x equal to 0 to find where the expression is undefined.
x=0
Step 4
Set the denominator in 1(2x)+3 equal to 0 to find where the expression is undefined.
(2x)+3=0
Step 5
Solve for x.
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Step 5.1
Subtract 3 from both sides of the equation.
2x=-3
Step 5.2
Find the LCD of the terms in the equation.
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Step 5.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
x,1
Step 5.2.2
The LCM of one and any expression is the expression.
x
x
Step 5.3
Multiply each term in 2x=-3 by x to eliminate the fractions.
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Step 5.3.1
Multiply each term in 2x=-3 by x.
2xx=-3x
Step 5.3.2
Simplify the left side.
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Step 5.3.2.1
Cancel the common factor of x.
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Step 5.3.2.1.1
Cancel the common factor.
2xx=-3x
Step 5.3.2.1.2
Rewrite the expression.
2=-3x
2=-3x
2=-3x
2=-3x
Step 5.4
Solve the equation.
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Step 5.4.1
Rewrite the equation as -3x=2.
-3x=2
Step 5.4.2
Divide each term in -3x=2 by -3 and simplify.
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Step 5.4.2.1
Divide each term in -3x=2 by -3.
-3x-3=2-3
Step 5.4.2.2
Simplify the left side.
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Step 5.4.2.2.1
Cancel the common factor of -3.
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Step 5.4.2.2.1.1
Cancel the common factor.
-3x-3=2-3
Step 5.4.2.2.1.2
Divide x by 1.
x=2-3
x=2-3
x=2-3
Step 5.4.2.3
Simplify the right side.
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Step 5.4.2.3.1
Move the negative in front of the fraction.
x=-23
x=-23
x=-23
x=-23
x=-23
Step 6
The domain is all values of x that make the expression defined.
Interval Notation:
(-,-23)(-23,0)(0,)
Set-Builder Notation:
{x|x0,-23}
Step 7
image of graph
(fog)(x),f(x)=1x+3,g(x)=2x
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