Algebra Examples

8^{2} + 6^{2} = c^{2}

$8^{2} + 6^{2} = c^{2}$

Rewrite the equation as

c^{2} = 8^{2} + 6^{2}

$c^{2} = 8^{2} + 6^{2}$ .

c^{2} = 8^{2} + 6^{2}

$c^{2} = 8^{2} + 6^{2}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

c = \pm \sqrt{8^{2} + 6^{2}}

$c = \pm \sqrt{8^{2} + 6^{2}}$

Simplify

\pm \sqrt{8^{2} + 6^{2}}

$\pm \sqrt{8^{2} + 6^{2}}$ .

Tap for more steps...

Raise

8

$8$ to the power of

2

$2$ .

c = \pm \sqrt{64 + 6^{2}}

$c = \pm \sqrt{64 + 6^{2}}$

Raise

6

$6$ to the power of

2

$2$ .

c = \pm \sqrt{64 + 36}

$c = \pm \sqrt{64 + 36}$

Add

64

$64$ and

36

$36$ .

c = \pm \sqrt{100}

$c = \pm \sqrt{100}$

Rewrite

100

$100$ as

10^{2}

$10^{2}$ .

c = \pm \sqrt{10^{2}}

$c = \pm \sqrt{10^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

c = \pm 10

$c = \pm 10$

c = \pm 10

$c = \pm 10$

The complete solution is the result of both the positive and negative portions of the solution.

Tap for more steps...

First, use the positive value of the

\pm

$\pm$ to find the first solution.

c = 10

$c = 10$

Next, use the negative value of the

\pm

$\pm$ to find the second solution.

c = - 10

$c = - 10$

The complete solution is the result of both the positive and negative portions of the solution.

c = 10, - 10

$c = 10, - 10$

c = 10, - 10

$c = 10, - 10$

8^{2} + 6^{2} = c^{2}

$8^{2} + 6^{2} = c^{2}$

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