Algebra Examples

Solve by Addition/Elimination x+y=2 x-y=4
x+y=2 x-y=4
Step 1
Multiply each equation by the value that makes the coefficients of x opposite.
x+y=2
(-1)(x-y)=(-1)(4)
Step 2
Simplify.
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Step 2.1
Simplify the left side.
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Step 2.1.1
Simplify (-1)(x-y).
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Step 2.1.1.1
Apply the distributive property.
x+y=2
-1x-1(-y)=(-1)(4)
Step 2.1.1.2
Rewrite -1x as -x.
x+y=2
-x-1(-y)=(-1)(4)
Step 2.1.1.3
Multiply -1(-y).
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Step 2.1.1.3.1
Multiply -1 by -1.
x+y=2
-x+1y=(-1)(4)
Step 2.1.1.3.2
Multiply y by 1.
x+y=2
-x+y=(-1)(4)
x+y=2
-x+y=(-1)(4)
x+y=2
-x+y=(-1)(4)
x+y=2
-x+y=(-1)(4)
Step 2.2
Simplify the right side.
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Step 2.2.1
Multiply -1 by 4.
x+y=2
-x+y=-4
x+y=2
-x+y=-4
x+y=2
-x+y=-4
Step 3
Add the two equations together to eliminate x from the system.
x+y=2
+-x+y=-4
2y=-2
Step 4
Divide each term in 2y=-2 by 2 and simplify.
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Step 4.1
Divide each term in 2y=-2 by 2.
2y2=-22
Step 4.2
Simplify the left side.
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Step 4.2.1
Cancel the common factor of 2.
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Step 4.2.1.1
Cancel the common factor.
2y2=-22
Step 4.2.1.2
Divide y by 1.
y=-22
y=-22
y=-22
Step 4.3
Simplify the right side.
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Step 4.3.1
Divide -2 by 2.
y=-1
y=-1
y=-1
Step 5
Substitute the value found for y into one of the original equations, then solve for x.
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Step 5.1
Substitute the value found for y into one of the original equations to solve for x.
x-1=2
Step 5.2
Move all terms not containing x to the right side of the equation.
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Step 5.2.1
Add 1 to both sides of the equation.
x=2+1
Step 5.2.2
Add 2 and 1.
x=3
x=3
x=3
Step 6
The solution to the independent system of equations can be represented as a point.
(3,-1)
Step 7
The result can be shown in multiple forms.
Point Form:
(3,-1)
Equation Form:
x=3,y=-1
Step 8
 [x2  12  π  xdx ]