Algebra Examples

$\frac{2 x}{x - 5}$

Step 1

Interchange the variables.

$x = \frac{2 y}{y - 5}$

Step 2

Solve for $y$ .

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Step 2.1

Multiply the equation by $y - 5$ .

$(y - 5) (x) = (\frac{2 y}{y - 5}) (y - 5)$

Step 2.2

Simplify the left side.

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Step 2.2.1

Apply the distributive property.

$y x - 5 x = (\frac{2 y}{y - 5}) (y - 5)$

Step 2.3

Simplify the right side.

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Step 2.3.1

Cancel the common factor of $y - 5$ .

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Step 2.3.1.1

Cancel the common factor.

$y x - 5 x = \frac{2 y}{y - 5} (y - 5)$

Step 2.3.1.2

Rewrite the expression.

$y x - 5 x = 2 y$

Step 2.4

Solve for $y$ .

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Step 2.4.1

Subtract $2 y$ from both sides of the equation.

$y x - 5 x - 2 y = 0$

Step 2.4.2

Add $5 x$ to both sides of the equation.

$y x - 2 y = 5 x$

Step 2.4.3

Factor $y$ out of $y x - 2 y$ .

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Step 2.4.3.1

Factor $y$ out of $y x$ .

$y (x) - 2 y = 5 x$

Step 2.4.3.2

Factor $y$ out of $- 2 y$ .

$y (x) + y \cdot - 2 = 5 x$

Step 2.4.3.3

Factor $y$ out of $y (x) + y \cdot - 2$ .

$y (x - 2) = 5 x$

Step 2.4.4

Divide each term in $y (x - 2) = 5 x$ by $x - 2$ and simplify.

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Step 2.4.4.1

Divide each term in $y (x - 2) = 5 x$ by $x - 2$ .

$\frac{y (x - 2)}{x - 2} = \frac{5 x}{x - 2}$

Step 2.4.4.2

Simplify the left side.

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Step 2.4.4.2.1

Cancel the common factor of $x - 2$ .

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Step 2.4.4.2.1.1

Cancel the common factor.

$\frac{y (x - 2)}{x - 2} = \frac{5 x}{x - 2}$

Step 2.4.4.2.1.2

Divide $y$ by $1$ .

$y = \frac{5 x}{x - 2}$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{5 x}{x - 2}$

Step 4

Verify if $f^{- 1} (x) = \frac{5 x}{x - 2}$ is the inverse of $f (x) = \frac{2 x}{x - 5}$ .

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Step 4.1

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Step 4.2

Evaluate $f^{- 1} (f (x))$ .

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Step 4.2.1

Set up the composite result function.

$f^{- 1} (f (x))$

Step 4.2.2

Evaluate $f^{- 1} (\frac{2 x}{x - 5})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{5 (\frac{2 x}{x - 5})}{(\frac{2 x}{x - 5}) - 2}$

Step 4.2.3

Combine $5$ and $\frac{2 x}{x - 5}$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 x}{x - 5} - 2}$

Step 4.2.4

Simplify the denominator.

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Step 4.2.4.1

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{x - 5}{x - 5}$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 x}{x - 5} - 2 \cdot \frac{x - 5}{x - 5}}$

Step 4.2.4.2

Combine $- 2$ and $\frac{x - 5}{x - 5}$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 x}{x - 5} + \frac{- 2 (x - 5)}{x - 5}}$

Step 4.2.4.3

Combine the numerators over the common denominator.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 x - 2 (x - 5)}{x - 5}}$

Step 4.2.4.4

Rewrite $\frac{2 x - 2 (x - 5)}{x - 5}$ in a factored form.

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Step 4.2.4.4.1

Factor $2$ out of $2 x - 2 (x - 5)$ .

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Step 4.2.4.4.1.1

Factor $2$ out of $2 x$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (x) - 2 (x - 5)}{x - 5}}$

Step 4.2.4.4.1.2

Factor $2$ out of $- 2 (x - 5)$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (x) + 2 (- (x - 5))}{x - 5}}$

Step 4.2.4.4.1.3

Factor $2$ out of $2 (x) + 2 (- (x - 5))$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (x - (x - 5))}{x - 5}}$

Step 4.2.4.4.2

Apply the distributive property.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (x - x + 5)}{x - 5}}$

Step 4.2.4.4.3

Multiply $- 1$ by $- 5$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (x - x + 5)}{x - 5}}$

Step 4.2.4.4.4

Subtract $x$ from $x$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 (0 + 5)}{x - 5}}$

Step 4.2.4.4.5

Add $0$ and $5$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{2 \cdot 5}{x - 5}}$

Step 4.2.4.5

Multiply $2$ by $5$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{5 (2 x)}{x - 5}}{\frac{10}{x - 5}}$

Step 4.2.5

Multiply $5$ by $2$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{\frac{10 x}{x - 5}}{\frac{10}{x - 5}}$

Step 4.2.6

Multiply the numerator by the reciprocal of the denominator.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{10 x}{x - 5} \cdot \frac{x - 5}{10}$

Step 4.2.7

Cancel the common factor of $10$ .

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Step 4.2.7.1

Factor $10$ out of $10 x$ .

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{10 (x)}{x - 5} \cdot \frac{x - 5}{10}$

Step 4.2.7.2

Cancel the common factor.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{10 x}{x - 5} \cdot \frac{x - 5}{10}$

Step 4.2.7.3

Rewrite the expression.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{x}{x - 5} \cdot (x - 5)$

Step 4.2.8

Cancel the common factor of $x - 5$ .

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Step 4.2.8.1

Cancel the common factor.

$f^{- 1} (\frac{2 x}{x - 5}) = \frac{x}{x - 5} \cdot (x - 5)$

Step 4.2.8.2

Rewrite the expression.

$f^{- 1} (\frac{2 x}{x - 5}) = x$

Step 4.3

Evaluate $f (f^{- 1} (x))$ .

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Step 4.3.1

Set up the composite result function.

$f (f^{- 1} (x))$

Step 4.3.2

Evaluate $f (\frac{5 x}{x - 2})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{5 x}{x - 2}) = \frac{2 (\frac{5 x}{x - 2})}{(\frac{5 x}{x - 2}) - 5}$

Step 4.3.3

Combine $2$ and $\frac{5 x}{x - 2}$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 x}{x - 2} - 5}$

Step 4.3.4

Simplify the denominator.

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Step 4.3.4.1

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{x - 2}{x - 2}$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 x}{x - 2} - 5 \cdot \frac{x - 2}{x - 2}}$

Step 4.3.4.2

Combine $- 5$ and $\frac{x - 2}{x - 2}$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 x}{x - 2} + \frac{- 5 (x - 2)}{x - 2}}$

Step 4.3.4.3

Combine the numerators over the common denominator.

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 x - 5 (x - 2)}{x - 2}}$

Step 4.3.4.4

Rewrite $\frac{5 x - 5 (x - 2)}{x - 2}$ in a factored form.

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Step 4.3.4.4.1

Factor $5$ out of $5 x - 5 (x - 2)$ .

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Step 4.3.4.4.1.1

Factor $5$ out of $5 x$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (x) - 5 (x - 2)}{x - 2}}$

Step 4.3.4.4.1.2

Factor $5$ out of $- 5 (x - 2)$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (x) + 5 (- (x - 2))}{x - 2}}$

Step 4.3.4.4.1.3

Factor $5$ out of $5 (x) + 5 (- (x - 2))$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (x - (x - 2))}{x - 2}}$

Step 4.3.4.4.2

Apply the distributive property.

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (x - x + 2)}{x - 2}}$

Step 4.3.4.4.3

Multiply $- 1$ by $- 2$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (x - x + 2)}{x - 2}}$

Step 4.3.4.4.4

Subtract $x$ from $x$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 (0 + 2)}{x - 2}}$

Step 4.3.4.4.5

Add $0$ and $2$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{5 \cdot 2}{x - 2}}$

Step 4.3.4.5

Multiply $5$ by $2$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{2 (5 x)}{x - 2}}{\frac{10}{x - 2}}$

Step 4.3.5

Multiply $2$ by $5$ .

$f (\frac{5 x}{x - 2}) = \frac{\frac{10 x}{x - 2}}{\frac{10}{x - 2}}$

Step 4.3.6

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{5 x}{x - 2}) = \frac{10 x}{x - 2} \cdot \frac{x - 2}{10}$

Step 4.3.7

Cancel the common factor of $10$ .

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Step 4.3.7.1

Factor $10$ out of $10 x$ .

$f (\frac{5 x}{x - 2}) = \frac{10 (x)}{x - 2} \cdot \frac{x - 2}{10}$

Step 4.3.7.2

Cancel the common factor.

$f (\frac{5 x}{x - 2}) = \frac{10 x}{x - 2} \cdot \frac{x - 2}{10}$

Step 4.3.7.3

Rewrite the expression.

$f (\frac{5 x}{x - 2}) = \frac{x}{x - 2} \cdot (x - 2)$

Step 4.3.8

Cancel the common factor of $x - 2$ .

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Step 4.3.8.1

Cancel the common factor.

$f (\frac{5 x}{x - 2}) = \frac{x}{x - 2} \cdot (x - 2)$

Step 4.3.8.2

Rewrite the expression.

$f (\frac{5 x}{x - 2}) = x$

Step 4.4

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{5 x}{x - 2}$ is the inverse of $f (x) = \frac{2 x}{x - 5}$ .

$f^{- 1} (x) = \frac{5 x}{x - 2}$