Algebra Examples

9 (p - 4) = - 18

$9 (p - 4) = - 18$

Step 1

Divide each term in

9 (p - 4) = - 18

$9 (p - 4) = - 18$ by

9

$9$ and simplify.

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Step 1.1

Divide each term in

9 (p - 4) = - 18

$9 (p - 4) = - 18$ by

9

$9$ .

\frac{9 (p - 4)}{9} = \frac{- 18}{9}

$\frac{9 (p - 4)}{9} = \frac{- 18}{9}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

9

$9$ .

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Step 1.2.1.1

Cancel the common factor.

\frac{9 (p - 4)}{9} = \frac{- 18}{9}

$\frac{9 (p - 4)}{9} = \frac{- 18}{9}$

Step 1.2.1.2

Divide

p - 4

$p - 4$ by

1

$1$ .

p - 4 = \frac{- 18}{9}

$p - 4 = \frac{- 18}{9}$

p - 4 = \frac{- 18}{9}

$p - 4 = \frac{- 18}{9}$

p - 4 = \frac{- 18}{9}

$p - 4 = \frac{- 18}{9}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

- 18

$- 18$ by

9

$9$ .

p - 4 = - 2

$p - 4 = - 2$

p - 4 = - 2

$p - 4 = - 2$

p - 4 = - 2

$p - 4 = - 2$

Step 2

Move all terms not containing

p

$p$ to the right side of the equation.

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Step 2.1

Add

4

$4$ to both sides of the equation.

p = - 2 + 4

$p = - 2 + 4$

Step 2.2

Add

- 2

$- 2$ and

4

$4$ .

p = 2

$p = 2$

p = 2

$p = 2$

9 (p - 4) = - 18

$9 (p - 4) = - 18$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$