Algebra Examples

$x^{2} + x - 7$

Step 1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 1$

$c = - 7$

Step 2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Tap for more steps...

Step 3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{1}{2 \cdot 1}$

Step 3.2

Cancel the common factor of $1$ .

Tap for more steps...

Step 3.2.1

Cancel the common factor.

$d = \frac{1}{2 \cdot 1}$

Step 3.2.2

Rewrite the expression.

$d = \frac{1}{2}$

Step 4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Tap for more steps...

Step 4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 7 - \frac{1^{2}}{4 \cdot 1}$

Step 4.2

Simplify the right side.

Tap for more steps...

Step 4.2.1

Simplify each term.

Tap for more steps...

Step 4.2.1.1

One to any power is one.

$e = - 7 - \frac{1}{4 \cdot 1}$

Step 4.2.1.2

Multiply $4$ by $1$ .

$e = - 7 - \frac{1}{4}$

Step 4.2.2

To write $- 7$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = - 7 \cdot \frac{4}{4} - \frac{1}{4}$

Step 4.2.3

Combine $- 7$ and $\frac{4}{4}$ .

$e = \frac{- 7 \cdot 4}{4} - \frac{1}{4}$

Step 4.2.4

Combine the numerators over the common denominator.

$e = \frac{- 7 \cdot 4 - 1}{4}$

Step 4.2.5

Simplify the numerator.

Tap for more steps...

Step 4.2.5.1

Multiply $- 7$ by $4$ .

$e = \frac{- 28 - 1}{4}$

Step 4.2.5.2

Subtract $1$ from $- 28$ .

$e = \frac{- 29}{4}$

Step 4.2.6

Move the negative in front of the fraction.

$e = - \frac{29}{4}$

Step 5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + \frac{1}{2})}^{2} - \frac{29}{4}$ .

${(x + \frac{1}{2})}^{2} - \frac{29}{4}$