Algebra Examples

$2 x = [\begin{array}{c} 4 & 12 \\ 1 & - 4 \end{array}] + [\begin{array}{c} - 2 & 0 \\ 3 & 4 \end{array}]$

Step 1

Simplify the right side of the equation.

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Add the corresponding elements.

$2 X = [\begin{array}{c} 4 - 2 & 12 + 0 \\ 1 + 3 & - 4 + 4 \end{array}]$

Simplify each element of the matrix $[\begin{array}{c} 4 - 2 & 12 + 0 \\ 1 + 3 & - 4 + 4 \end{array}]$ .

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Simplify $4 - 2$ .

$2 X = [\begin{array}{c} 2 & 12 + 0 \\ 1 + 3 & - 4 + 4 \end{array}]$

Simplify $12 + 0$ .

$2 X = [\begin{array}{c} 2 & 12 \\ 1 + 3 & - 4 + 4 \end{array}]$

Simplify $1 + 3$ .

$2 X = [\begin{array}{c} 2 & 12 \\ 4 & - 4 + 4 \end{array}]$

Simplify $- 4 + 4$ .

$2 X = [\begin{array}{c} 2 & 12 \\ 4 & 0 \end{array}]$

Step 2

Multiply both sides of the equation by $\frac{1}{2}$ .

$\frac{1}{2} \cdot (2 X) = \frac{1}{2} \cdot [\begin{array}{c} 2 & 12 \\ 4 & 0 \end{array}]$

Step 3

Simplify both sides of the equation.

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Cancel the common factor of $2$ .

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Factor $2$ out of $2 X$ .

$\frac{1}{2} \cdot (2 (X)) = \frac{1}{2} \cdot [\begin{array}{c} 2 & 12 \\ 4 & 0 \end{array}]$

Cancel the common factor.

$\frac{1}{2} \cdot (2 X) = \frac{1}{2} \cdot [\begin{array}{c} 2 & 12 \\ 4 & 0 \end{array}]$

Rewrite the expression.

$X = \frac{1}{2} \cdot [\begin{array}{c} 2 & 12 \\ 4 & 0 \end{array}]$

Simplify the right side of the equation.

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Multiply $\frac{1}{2}$ by each element of the matrix.

$X = [\begin{array}{c} \frac{1}{2} \cdot 2 & \frac{1}{2} \cdot 12 \\ \frac{1}{2} \cdot 4 & \frac{1}{2} \cdot 0 \end{array}]$

Simplify each element in the matrix.

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Rearrange $\frac{1}{2} \cdot 2$ .

$X = [\begin{array}{c} 1 & \frac{1}{2} \cdot 12 \\ \frac{1}{2} \cdot 4 & \frac{1}{2} \cdot 0 \end{array}]$

Rearrange $\frac{1}{2} \cdot 12$ .

$X = [\begin{array}{c} 1 & 6 \\ \frac{1}{2} \cdot 4 & \frac{1}{2} \cdot 0 \end{array}]$

Rearrange $\frac{1}{2} \cdot 4$ .

$X = [\begin{array}{c} 1 & 6 \\ 2 & \frac{1}{2} \cdot 0 \end{array}]$

Rearrange $\frac{1}{2} \cdot 0$ .

$X = [\begin{array}{c} 1 & 6 \\ 2 & 0 \end{array}]$