Algebra Examples

$y = 3 x + 2$ , $3 y = 9 x + 6$

Step 1

Divide each term in $3 y = 9 x + 6$ by $3$ and simplify.

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Step 1.1

Divide each term in $3 y = 9 x + 6$ by $3$ .

$\frac{3 y}{3} = \frac{9 x}{3} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $3$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{9 x}{3} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.2.1.2

Divide $y$ by $1$ .

$y = \frac{9 x}{3} + \frac{6}{3}$

$y = 3 x + 2$

$y = \frac{9 x}{3} + \frac{6}{3}$

$y = 3 x + 2$

$y = \frac{9 x}{3} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3

Simplify the right side.

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Step 1.3.1

Simplify each term.

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Step 1.3.1.1

Cancel the common factor of $9$ and $3$ .

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Step 1.3.1.1.1

Factor $3$ out of $9 x$ .

$y = \frac{3 (3 x)}{3} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3.1.1.2

Cancel the common factors.

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Step 1.3.1.1.2.1

Factor $3$ out of $3$ .

$y = \frac{3 (3 x)}{3 (1)} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3.1.1.2.2

Cancel the common factor.

$y = \frac{3 (3 x)}{3 \cdot 1} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3.1.1.2.3

Rewrite the expression.

$y = \frac{3 x}{1} + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3.1.1.2.4

Divide $3 x$ by $1$ .

$y = 3 x + \frac{6}{3}$

$y = 3 x + 2$

$y = 3 x + \frac{6}{3}$

$y = 3 x + 2$

$y = 3 x + \frac{6}{3}$

$y = 3 x + 2$

Step 1.3.1.2

Divide $6$ by $3$ .

$y = 3 x + 2$

Step 2

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Step 3

Nothing further can be done with this topic. Please check the expression entered or try another topic.

$y = 3 x + 2, 3 y = 9 x + 6$

Step 4