Algebra Examples

$f (x) = 12 x + 27$

Step 1

Set $12 x + 27$ equal to $0$ .

$12 x + 27 = 0$

Step 2

Solve for $x$ .

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Step 2.1

Subtract $27$ from both sides of the equation.

$12 x = - 27$

Step 2.2

Divide each term in $12 x = - 27$ by $12$ and simplify.

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Step 2.2.1

Divide each term in $12 x = - 27$ by $12$ .

$\frac{12 x}{12} = \frac{- 27}{12}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $12$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{12 x}{12} = \frac{- 27}{12}$

Step 2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 27}{12}$

$x = \frac{- 27}{12}$

$x = \frac{- 27}{12}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Cancel the common factor of $- 27$ and $12$ .

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Step 2.2.3.1.1

Factor $3$ out of $- 27$ .

$x = \frac{3 (- 9)}{12}$

Step 2.2.3.1.2

Cancel the common factors.

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Step 2.2.3.1.2.1

Factor $3$ out of $12$ .

$x = \frac{3 \cdot - 9}{3 \cdot 4}$

Step 2.2.3.1.2.2

Cancel the common factor.

$x = \frac{3 \cdot - 9}{3 \cdot 4}$

Step 2.2.3.1.2.3

Rewrite the expression.

$x = \frac{- 9}{4}$

$x = \frac{- 9}{4}$

$x = \frac{- 9}{4}$

Step 2.2.3.2

Move the negative in front of the fraction.

$x = - \frac{9}{4}$

$x = - \frac{9}{4}$

$x = - \frac{9}{4}$

$x = - \frac{9}{4}$

Step 3

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$