Algebra Examples

Find Where Undefined/Discontinuous (9k^2-33k+10)/(18k^3-200k)
Step 1
Set the denominator in equal to to find where the expression is undefined.
Step 2
Solve for .
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Step 2.1
Factor the left side of the equation.
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Step 2.1.1
Factor out of .
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Step 2.1.1.1
Factor out of .
Step 2.1.1.2
Factor out of .
Step 2.1.1.3
Factor out of .
Step 2.1.2
Rewrite as .
Step 2.1.3
Rewrite as .
Step 2.1.4
Factor.
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Step 2.1.4.1
Since both terms are perfect squares, factor using the difference of squares formula, where and .
Step 2.1.4.2
Remove unnecessary parentheses.
Step 2.2
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Step 2.3
Set equal to .
Step 2.4
Set equal to and solve for .
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Step 2.4.1
Set equal to .
Step 2.4.2
Solve for .
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Step 2.4.2.1
Subtract from both sides of the equation.
Step 2.4.2.2
Divide each term in by and simplify.
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Step 2.4.2.2.1
Divide each term in by .
Step 2.4.2.2.2
Simplify the left side.
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Step 2.4.2.2.2.1
Cancel the common factor of .
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Step 2.4.2.2.2.1.1
Cancel the common factor.
Step 2.4.2.2.2.1.2
Divide by .
Step 2.4.2.2.3
Simplify the right side.
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Step 2.4.2.2.3.1
Move the negative in front of the fraction.
Step 2.5
Set equal to and solve for .
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Step 2.5.1
Set equal to .
Step 2.5.2
Solve for .
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Step 2.5.2.1
Add to both sides of the equation.
Step 2.5.2.2
Divide each term in by and simplify.
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Step 2.5.2.2.1
Divide each term in by .
Step 2.5.2.2.2
Simplify the left side.
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Step 2.5.2.2.2.1
Cancel the common factor of .
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Step 2.5.2.2.2.1.1
Cancel the common factor.
Step 2.5.2.2.2.1.2
Divide by .
Step 2.6
The final solution is all the values that make true.
Step 3
The equation is undefined where the denominator equals , the argument of a square root is less than , or the argument of a logarithm is less than or equal to .
Step 4