Algebra Examples

$\frac{x + 5}{3 x^{2} - 3}$

Step 1

Set the denominator in $\frac{x + 5}{3 x^{2} - 3}$ equal to $0$ to find where the expression is undefined.

$3 x^{2} - 3 = 0$

Step 2

Solve for $x$ .

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Step 2.1

Add $3$ to both sides of the equation.

$3 x^{2} = 3$

Step 2.2

Divide each term in $3 x^{2} = 3$ by $3$ and simplify.

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Step 2.2.1

Divide each term in $3 x^{2} = 3$ by $3$ .

$\frac{3 x^{2}}{3} = \frac{3}{3}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $3$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{3 x^{2}}{3} = \frac{3}{3}$

Step 2.2.2.1.2

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{3}{3}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Divide $3$ by $3$ .

$x^{2} = 1$

Step 2.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

Step 2.4

Any root of $1$ is $1$ .

$x = \pm 1$

Step 2.5

The complete solution is the result of both the positive and negative portions of the solution.

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Step 2.5.1

First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Step 2.5.2

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

Step 2.5.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$

Step 3

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 1, x = 1$

Step 4