Algebra Examples

$8 x + 25 y = 5$

Step 1

Solve the equation for $y$ .

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Step 1.1

Subtract $8 x$ from both sides of the equation.

$25 y = 5 - 8 x$

Step 1.2

Divide each term in $25 y = 5 - 8 x$ by $25$ and simplify.

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Step 1.2.1

Divide each term in $25 y = 5 - 8 x$ by $25$ .

$\frac{25 y}{25} = \frac{5}{25} + \frac{- 8 x}{25}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $25$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{25 y}{25} = \frac{5}{25} + \frac{- 8 x}{25}$

Step 1.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{5}{25} + \frac{- 8 x}{25}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Cancel the common factor of $5$ and $25$ .

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Step 1.2.3.1.1.1

Factor $5$ out of $5$ .

$y = \frac{5 (1)}{25} + \frac{- 8 x}{25}$

Step 1.2.3.1.1.2

Cancel the common factors.

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Step 1.2.3.1.1.2.1

Factor $5$ out of $25$ .

$y = \frac{5 \cdot 1}{5 \cdot 5} + \frac{- 8 x}{25}$

Step 1.2.3.1.1.2.2

Cancel the common factor.

$y = \frac{5 \cdot 1}{5 \cdot 5} + \frac{- 8 x}{25}$

Step 1.2.3.1.1.2.3

Rewrite the expression.

$y = \frac{1}{5} + \frac{- 8 x}{25}$

Step 1.2.3.1.2

Move the negative in front of the fraction.

$y = \frac{1}{5} - \frac{8 x}{25}$

Step 2

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be $0$ or $1$ for each of its variables. In this case, the degree of variable $y$ is $1$ and the degree of variable $x$ is $1$ .

Linear