Algebra Examples

${(- p + q)}^{5}$

Step 1

Use the binomial expansion theorem to find each term. The binomial theorem states ${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

$\sum_{k = 0}^{5} \frac{5!}{(5 - k)! k!} \cdot {(- p)}^{5 - k} \cdot {(q)}^{k}$

Step 2

Expand the summation.

$\frac{5!}{(5 - 0)! 0!} \cdot {(- p)}^{5 - 0} \cdot {(q)}^{0} + \frac{5!}{(5 - 1)! 1!} \cdot {(- p)}^{5 - 1} \cdot {(q)}^{1} + \dots + \frac{5!}{(5 - 5)! 5!} \cdot {(- p)}^{5 - 5} \cdot {(q)}^{5}$

Step 3

Simplify the exponents for each term of the expansion.

$1 \cdot {(- p)}^{5} \cdot {(q)}^{0} + 5 \cdot {(- p)}^{4} \cdot {(q)}^{1} + \dots + 1 \cdot {(- p)}^{0} \cdot {(q)}^{5}$

Step 4

Simplify the polynomial result.

$- p^{5} + 5 p^{4} q - 10 p^{3} q^{2} + 10 p^{2} q^{3} - 5 p q^{4} + q^{5}$