Algebra Examples

$\log_{5} (4.7) + \log_{5} (2)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{5} (4.7 \cdot 2)$

Step 2

Multiply $4.7$ by $2$ .

$\log_{5} (9.4)$

Step 3

Log base $5$ of $9.4$ is approximately $1.3922312$ .

$1.3922312$