Algebra Examples

$x^{2} + 6 x = 15$

Step 1

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(3)}^{2}$

Step 2

Add the term to each side of the equation.

$x^{2} + 6 x + {(3)}^{2} = 15 + {(3)}^{2}$

Step 3

Simplify the equation.

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Step 3.1

Simplify the left side.

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Step 3.1.1

Raise $3$ to the power of $2$ .

$x^{2} + 6 x + 9 = 15 + {(3)}^{2}$

Step 3.2

Simplify the right side.

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Step 3.2.1

Simplify $15 + {(3)}^{2}$ .

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Step 3.2.1.1

Raise $3$ to the power of $2$ .

$x^{2} + 6 x + 9 = 15 + 9$

Step 3.2.1.2

Add $15$ and $9$ .

$x^{2} + 6 x + 9 = 24$

Step 4

Factor the perfect trinomial square into ${(x + 3)}^{2}$ .

${(x + 3)}^{2} = 24$

Step 5

Solve the equation for $x$ .

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Step 5.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 3 = \pm \sqrt{24}$

Step 5.2

Simplify $\pm \sqrt{24}$ .

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Step 5.2.1

Rewrite $24$ as $2^{2} \cdot 6$ .

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Step 5.2.1.1

Factor $4$ out of $24$ .

$x + 3 = \pm \sqrt{4 (6)}$

Step 5.2.1.2

Rewrite $4$ as $2^{2}$ .

$x + 3 = \pm \sqrt{2^{2} \cdot 6}$

Step 5.2.2

Pull terms out from under the radical.

$x + 3 = \pm 2 \sqrt{6}$

Step 5.3

Subtract $3$ from both sides of the equation.

$x = \pm 2 \sqrt{6} - 3$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = \pm 2 \sqrt{6} - 3$

Decimal Form:

$x = 1.89897948 \dots, - 7.89897948 \dots$