Algebra Examples

$f (x) = \frac{2}{3} x + 10$

Step 1

Write $f (x) = \frac{2}{3} x + 10$ as an equation.

$y = \frac{2}{3} x + 10$

Step 2

Interchange the variables.

$x = \frac{2}{3} y + 10$

Step 3

Solve for $y$ .

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Step 3.1

Rewrite the equation as $\frac{2}{3} y + 10 = x$ .

$\frac{2}{3} y + 10 = x$

Step 3.2

Combine $\frac{2}{3}$ and $y$ .

$\frac{2 y}{3} + 10 = x$

Step 3.3

Subtract $10$ from both sides of the equation.

$\frac{2 y}{3} = x - 10$

Step 3.4

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} \cdot \frac{2 y}{3} = \frac{3}{2} (x - 10)$

Step 3.5

Simplify both sides of the equation.

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Step 3.5.1

Simplify the left side.

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Step 3.5.1.1

Simplify $\frac{3}{2} \cdot \frac{2 y}{3}$ .

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Step 3.5.1.1.1

Cancel the common factor of $3$ .

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Step 3.5.1.1.1.1

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 y}{3} = \frac{3}{2} (x - 10)$

Step 3.5.1.1.1.2

Rewrite the expression.

$\frac{1}{2} (2 y) = \frac{3}{2} (x - 10)$

Step 3.5.1.1.2

Cancel the common factor of $2$ .

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Step 3.5.1.1.2.1

Factor $2$ out of $2 y$ .

$\frac{1}{2} (2 (y)) = \frac{3}{2} (x - 10)$

Step 3.5.1.1.2.2

Cancel the common factor.

$\frac{1}{2} (2 y) = \frac{3}{2} (x - 10)$

Step 3.5.1.1.2.3

Rewrite the expression.

$y = \frac{3}{2} (x - 10)$

Step 3.5.2

Simplify the right side.

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Step 3.5.2.1

Simplify $\frac{3}{2} (x - 10)$ .

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Step 3.5.2.1.1

Apply the distributive property.

$y = \frac{3}{2} x + \frac{3}{2} \cdot - 10$

Step 3.5.2.1.2

Combine $\frac{3}{2}$ and $x$ .

$y = \frac{3 x}{2} + \frac{3}{2} \cdot - 10$

Step 3.5.2.1.3

Cancel the common factor of $2$ .

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Step 3.5.2.1.3.1

Factor $2$ out of $- 10$ .

$y = \frac{3 x}{2} + \frac{3}{2} \cdot (2 (- 5))$

Step 3.5.2.1.3.2

Cancel the common factor.

$y = \frac{3 x}{2} + \frac{3}{2} \cdot (2 \cdot - 5)$

Step 3.5.2.1.3.3

Rewrite the expression.

$y = \frac{3 x}{2} + 3 \cdot - 5$

Step 3.5.2.1.4

Multiply $3$ by $- 5$ .

$y = \frac{3 x}{2} - 15$

Step 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{3 x}{2} - 15$

Step 5

Verify if $f^{- 1} (x) = \frac{3 x}{2} - 15$ is the inverse of $f (x) = \frac{2}{3} x + 10$ .

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Step 5.1

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Step 5.2

Evaluate $f^{- 1} (f (x))$ .

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Step 5.2.1

Set up the composite result function.

$f^{- 1} (f (x))$

Step 5.2.2

Evaluate $f^{- 1} (\frac{2}{3} x + 10)$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 (\frac{2}{3} x + 10)}{2} - 15$

Step 5.2.3

Simplify each term.

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Step 5.2.3.1

Simplify the numerator.

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Step 5.2.3.1.1

Combine $\frac{2}{3}$ and $x$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 (\frac{2 x}{3} + 10)}{2} - 15$

Step 5.2.3.1.2

Factor $2$ out of $\frac{2 x}{3} + 10$ .

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Step 5.2.3.1.2.1

Factor $2$ out of $\frac{2 x}{3}$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 (2 (\frac{x}{3}) + 10)}{2} - 15$

Step 5.2.3.1.2.2

Factor $2$ out of $10$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 (2 (\frac{x}{3}) + 2 \cdot 5)}{2} - 15$

Step 5.2.3.1.2.3

Factor $2$ out of $2 \frac{x}{3} + 2 \cdot 5$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 (2 (\frac{x}{3} + 5))}{2} - 15$

$f^{- 1} (\frac{2}{3} x + 10) = \frac{3 \cdot (2 (\frac{x}{3} + 5))}{2} - 15$

Step 5.2.3.1.3

Multiply $3$ by $2$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{6 (\frac{x}{3} + 5)}{2} - 15$

Step 5.2.3.1.4

To write $5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{6 (\frac{x}{3} + 5 \cdot \frac{3}{3})}{2} - 15$

Step 5.2.3.1.5

Combine $5$ and $\frac{3}{3}$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{6 (\frac{x}{3} + \frac{5 \cdot 3}{3})}{2} - 15$

Step 5.2.3.1.6

Combine the numerators over the common denominator.

$f^{- 1} (\frac{2}{3} x + 10) = \frac{6 (\frac{x + 5 \cdot 3}{3})}{2} - 15$

Step 5.2.3.1.7

Multiply $5$ by $3$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{6 (\frac{x + 15}{3})}{2} - 15$

Step 5.2.3.2

Combine $6$ and $\frac{x + 15}{3}$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{\frac{6 (x + 15)}{3}}{2} - 15$

Step 5.2.3.3

Reduce the expression by cancelling the common factors.

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Step 5.2.3.3.1

Reduce the expression $\frac{6 (x + 15)}{3}$ by cancelling the common factors.

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Step 5.2.3.3.1.1

Factor $3$ out of $6 (x + 15)$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{\frac{3 (2 (x + 15))}{3}}{2} - 15$

Step 5.2.3.3.1.2

Factor $3$ out of $3$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{\frac{3 (2 (x + 15))}{3 (1)}}{2} - 15$

Step 5.2.3.3.1.3

Cancel the common factor.

$f^{- 1} (\frac{2}{3} x + 10) = \frac{\frac{3 (2 (x + 15))}{3 \cdot 1}}{2} - 15$

Step 5.2.3.3.1.4

Rewrite the expression.

$f^{- 1} (\frac{2}{3} x + 10) = \frac{\frac{2 (x + 15)}{1}}{2} - 15$

Step 5.2.3.3.2

Divide $2 (x + 15)$ by $1$ .

$f^{- 1} (\frac{2}{3} x + 10) = \frac{2 (x + 15)}{2} - 15$

Step 5.2.3.4

Cancel the common factor of $2$ .

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Step 5.2.3.4.1

Cancel the common factor.

$f^{- 1} (\frac{2}{3} x + 10) = \frac{2 (x + 15)}{2} - 15$

Step 5.2.3.4.2

Divide $x + 15$ by $1$ .

$f^{- 1} (\frac{2}{3} x + 10) = x + 15 - 15$

Step 5.2.4

Combine the opposite terms in $x + 15 - 15$ .

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Step 5.2.4.1

Subtract $15$ from $15$ .

$f^{- 1} (\frac{2}{3} x + 10) = x + 0$

Step 5.2.4.2

Add $x$ and $0$ .

$f^{- 1} (\frac{2}{3} x + 10) = x$

Step 5.3

Evaluate $f (f^{- 1} (x))$ .

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Step 5.3.1

Set up the composite result function.

$f (f^{- 1} (x))$

Step 5.3.2

Evaluate $f (\frac{3 x}{2} - 15)$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{3 x}{2} - 15) = \frac{2}{3} \cdot (\frac{3 x}{2} - 15) + 10$

Step 5.3.3

Simplify each term.

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Step 5.3.3.1

Apply the distributive property.

$f (\frac{3 x}{2} - 15) = \frac{2}{3} \cdot \frac{3 x}{2} + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.2

Cancel the common factor of $2$ .

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Step 5.3.3.2.1

Cancel the common factor.

$f (\frac{3 x}{2} - 15) = \frac{2}{3} \cdot \frac{3 x}{2} + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.2.2

Rewrite the expression.

$f (\frac{3 x}{2} - 15) = \frac{1}{3} \cdot (3 x) + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.3

Cancel the common factor of $3$ .

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Step 5.3.3.3.1

Factor $3$ out of $3 x$ .

$f (\frac{3 x}{2} - 15) = \frac{1}{3} \cdot (3 (x)) + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.3.2

Cancel the common factor.

$f (\frac{3 x}{2} - 15) = \frac{1}{3} \cdot (3 x) + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.3.3

Rewrite the expression.

$f (\frac{3 x}{2} - 15) = x + \frac{2}{3} \cdot - 15 + 10$

Step 5.3.3.4

Cancel the common factor of $3$ .

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Step 5.3.3.4.1

Factor $3$ out of $- 15$ .

$f (\frac{3 x}{2} - 15) = x + \frac{2}{3} \cdot (3 (- 5)) + 10$

Step 5.3.3.4.2

Cancel the common factor.

$f (\frac{3 x}{2} - 15) = x + \frac{2}{3} \cdot (3 \cdot - 5) + 10$

Step 5.3.3.4.3

Rewrite the expression.

$f (\frac{3 x}{2} - 15) = x + 2 \cdot - 5 + 10$

Step 5.3.3.5

Multiply $2$ by $- 5$ .

$f (\frac{3 x}{2} - 15) = x - 10 + 10$

Step 5.3.4

Combine the opposite terms in $x - 10 + 10$ .

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Step 5.3.4.1

Add $- 10$ and $10$ .

$f (\frac{3 x}{2} - 15) = x + 0$

Step 5.3.4.2

Add $x$ and $0$ .

$f (\frac{3 x}{2} - 15) = x$

Step 5.4

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{3 x}{2} - 15$ is the inverse of $f (x) = \frac{2}{3} x + 10$ .

$f^{- 1} (x) = \frac{3 x}{2} - 15$