Algebra Examples

$\log_{9} (27) + \log_{9} (3)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{9} (27 \cdot 3)$

Step 2

Multiply $27$ by $3$ .

$\log_{9} (81)$

Step 3

Logarithm base $9$ of $81$ is $2$ .

$2$