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Algebra Examples
x(x-2)=48x(x−2)=48
Step 1
Step 1.1
Simplify the left side.
Step 1.1.1
Simplify x(x-2)x(x−2).
Step 1.1.1.1
Apply the distributive property.
x⋅x+x⋅-2=48x⋅x+x⋅−2=48
Step 1.1.1.2
Simplify the expression.
Step 1.1.1.2.1
Multiply xx by xx.
x2+x⋅-2=48x2+x⋅−2=48
Step 1.1.1.2.2
Move -2−2 to the left of xx.
x2-2x=48x2−2x=48
x2-2x=48x2−2x=48
x2-2x=48x2−2x=48
x2-2x=48x2−2x=48
Step 1.2
Subtract 4848 from both sides of the equation.
x2-2x-48=0x2−2x−48=0
x2-2x-48=0x2−2x−48=0
Step 2
Use the quadratic formula to find the solutions.
-b±√b2-4(ac)2a−b±√b2−4(ac)2a
Step 3
Substitute the values a=1a=1, b=-2b=−2, and c=-48c=−48 into the quadratic formula and solve for xx.
2±√(-2)2-4⋅(1⋅-48)2⋅12±√(−2)2−4⋅(1⋅−48)2⋅1
Step 4
Step 4.1
Simplify the numerator.
Step 4.1.1
Raise -2−2 to the power of 22.
x=2±√4-4⋅1⋅-482⋅1x=2±√4−4⋅1⋅−482⋅1
Step 4.1.2
Multiply -4⋅1⋅-48−4⋅1⋅−48.
Step 4.1.2.1
Multiply -4−4 by 11.
x=2±√4-4⋅-482⋅1x=2±√4−4⋅−482⋅1
Step 4.1.2.2
Multiply -4−4 by -48−48.
x=2±√4+1922⋅1x=2±√4+1922⋅1
x=2±√4+1922⋅1x=2±√4+1922⋅1
Step 4.1.3
Add 44 and 192192.
x=2±√1962⋅1x=2±√1962⋅1
Step 4.1.4
Rewrite 196196 as 142142.
x=2±√1422⋅1x=2±√1422⋅1
Step 4.1.5
Pull terms out from under the radical, assuming positive real numbers.
x=2±142⋅1
x=2±142⋅1
Step 4.2
Multiply 2 by 1.
x=2±142
Step 4.3
Simplify 2±142.
x=1±7
x=1±7
Step 5
The final answer is the combination of both solutions.
x=8,-6