Algebra Examples

$3 (5 j + 2) = 2 (3 j - 6)$

Step 1

Simplify

$3 (5 j + 2)$ .

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Step 1.1

Rewrite.

$0 + 0 + 3 (5 j + 2) = 2 (3 j - 6)$

Step 1.2

Simplify by adding zeros.

$3 (5 j + 2) = 2 (3 j - 6)$

Step 1.3

Apply the distributive property.

$3 (5 j) + 3 \cdot 2 = 2 (3 j - 6)$

Step 1.4

Multiply.

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Step 1.4.1

Multiply

$5$ by

$3$ .

$15 j + 3 \cdot 2 = 2 (3 j - 6)$

Step 1.4.2

Multiply

$3$ by

$2$ .

$15 j + 6 = 2 (3 j - 6)$

$15 j + 6 = 2 (3 j - 6)$

$15 j + 6 = 2 (3 j - 6)$

Step 2

Simplify

$2 (3 j - 6)$ .

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Step 2.1

Apply the distributive property.

$15 j + 6 = 2 (3 j) + 2 \cdot - 6$

Step 2.2

Multiply.

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Step 2.2.1

Multiply

$3$ by

$2$ .

$15 j + 6 = 6 j + 2 \cdot - 6$

Step 2.2.2

Multiply

$2$ by

$- 6$ .

$15 j + 6 = 6 j - 12$

$15 j + 6 = 6 j - 12$

$15 j + 6 = 6 j - 12$

Step 3

Move all terms containing

$j$ to the left side of the equation.

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Step 3.1

Subtract

$6 j$ from both sides of the equation.

$15 j + 6 - 6 j = - 12$

Step 3.2

Subtract

$6 j$ from

$15 j$ .

$9 j + 6 = - 12$

$9 j + 6 = - 12$

Step 4

Move all terms not containing

$j$ to the right side of the equation.

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Step 4.1

Subtract

$6$ from both sides of the equation.

$9 j = - 12 - 6$

Step 4.2

Subtract

$6$ from

$- 12$ .

$9 j = - 18$

$9 j = - 18$

Step 5

Divide each term in

$9 j = - 18$ by

$9$ and simplify.

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Step 5.1

Divide each term in

$9 j = - 18$ by

$9$ .

$\frac{9 j}{9} = \frac{- 18}{9}$

Step 5.2

Simplify the left side.

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Step 5.2.1

Cancel the common factor of

$9$ .

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Step 5.2.1.1

Cancel the common factor.

$\frac{9 j}{9} = \frac{- 18}{9}$

Step 5.2.1.2

Divide

$j$ by

$1$ .

$j = \frac{- 18}{9}$

$j = \frac{- 18}{9}$

$j = \frac{- 18}{9}$

Step 5.3

Simplify the right side.

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Step 5.3.1

Divide

$- 18$ by

$9$ .

$j = - 2$

$j = - 2$

$j = - 2$

$3 (5 j + 2) = 2 (3 j - 6)$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$