Algebra Examples

x - y = 1

$x - y = 1$ ,

x + y = 3

$x + y = 3$

Step 1

Subtract

x

$x$ from both sides of the equation.

- y = 1 - x

$- y = 1 - x$

x + y = 3

$x + y = 3$

Step 2

Divide each term in

- y = 1 - x

$- y = 1 - x$ by

- 1

$- 1$ and simplify.

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Step 2.1

Divide each term in

- y = 1 - x

$- y = 1 - x$ by

- 1

$- 1$ .

\frac{- y}{- 1} = \frac{1}{- 1} + \frac{- x}{- 1}

$\frac{- y}{- 1} = \frac{1}{- 1} + \frac{- x}{- 1}$

x + y = 3

$x + y = 3$

Step 2.2

Simplify the left side.

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Step 2.2.1

Dividing two negative values results in a positive value.

\frac{y}{1} = \frac{1}{- 1} + \frac{- x}{- 1}

$\frac{y}{1} = \frac{1}{- 1} + \frac{- x}{- 1}$

x + y = 3

$x + y = 3$

Step 2.2.2

Divide

y

$y$ by

1

$1$ .

y = \frac{1}{- 1} + \frac{- x}{- 1}

$y = \frac{1}{- 1} + \frac{- x}{- 1}$

x + y = 3

$x + y = 3$

y = \frac{1}{- 1} + \frac{- x}{- 1}

$y = \frac{1}{- 1} + \frac{- x}{- 1}$

x + y = 3

$x + y = 3$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Divide

1

$1$ by

- 1

$- 1$ .

y = - 1 + \frac{- x}{- 1}

$y = - 1 + \frac{- x}{- 1}$

x + y = 3

$x + y = 3$

Step 2.3.1.2

Dividing two negative values results in a positive value.

y = - 1 + \frac{x}{1}

$y = - 1 + \frac{x}{1}$

x + y = 3

$x + y = 3$

Step 2.3.1.3

Divide

x

$x$ by

1

$1$ .

y = - 1 + x

$y = - 1 + x$

x + y = 3

$x + y = 3$

y = - 1 + x

$y = - 1 + x$

x + y = 3

$x + y = 3$

y = - 1 + x

$y = - 1 + x$

x + y = 3

$x + y = 3$

y = - 1 + x

$y = - 1 + x$

x + y = 3

$x + y = 3$

Step 3

Subtract

x

$x$ from both sides of the equation.

y = 3 - x

$y = 3 - x$

y = - 1 + x

$y = - 1 + x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

(2, 1)

$(2, 1)$

Step 5