Enter a problem...
Algebra Examples
x3-a3x3−a3
Step 1
Since both terms are perfect cubes, factor using the difference of cubes formula, a3-b3=(a-b)(a2+ab+b2)a3−b3=(a−b)(a2+ab+b2) where a=xa=x and b=ab=a.
(x-a)(x2+xa+a2)(x−a)(x2+xa+a2)