Algebra Examples

3 (x - 4) = 3 x - 12

$3 (x - 4) = 3 x - 12$

Step 1

Move all the expressions to the left side of the equation.

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Step 1.1

Subtract

3 x

$3 x$ from both sides of the equation.

3 (x - 4) - 3 x = - 12

$3 (x - 4) - 3 x = - 12$

Step 1.2

Add

12

$12$ to both sides of the equation.

3 (x - 4) - 3 x + 12 = 0

$3 (x - 4) - 3 x + 12 = 0$

3 (x - 4) - 3 x + 12 = 0

$3 (x - 4) - 3 x + 12 = 0$

Step 2

Simplify

3 (x - 4) - 3 x + 12

$3 (x - 4) - 3 x + 12$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

3 x + 3 \cdot - 4 - 3 x + 12 = 0

$3 x + 3 \cdot - 4 - 3 x + 12 = 0$

Step 2.1.2

Multiply

3

$3$ by

- 4

$- 4$ .

3 x - 12 - 3 x + 12 = 0

$3 x - 12 - 3 x + 12 = 0$

3 x - 12 - 3 x + 12 = 0

$3 x - 12 - 3 x + 12 = 0$

Step 2.2

Combine the opposite terms in

3 x - 12 - 3 x + 12

$3 x - 12 - 3 x + 12$ .

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Step 2.2.1

Subtract

3 x

$3 x$ from

3 x

$3 x$ .

0 - 12 + 12 = 0

$0 - 12 + 12 = 0$

Step 2.2.2

Subtract

12

$12$ from

0

$0$ .

- 12 + 12 = 0

$- 12 + 12 = 0$

Step 2.2.3

Add

- 12

$- 12$ and

12

$12$ .

0 = 0

$0 = 0$

0 = 0

$0 = 0$

0 = 0

$0 = 0$

Step 3

Since

0 = 0

$0 = 0$ , the equation will always be true.

Always true

3 (x - 4) = 3 x - 12

$3 (x - 4) = 3 x - 12$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$