Algebra Examples

Solve for x log base 27 of x=2/3
log27(x)=23log27(x)=23
Step 1
Rewrite log27(x)=23log27(x)=23 in exponential form using the definition of a logarithm. If xx and bb are positive real numbers and b1b1, then logb(x)=ylogb(x)=y is equivalent to by=xby=x.
2723=x2723=x
Step 2
Solve for xx.
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Step 2.1
Rewrite the equation as x=2723x=2723.
x=2723x=2723
Step 2.2
Simplify 27232723.
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Step 2.2.1
Simplify the expression.
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Step 2.2.1.1
Rewrite 2727 as 3333.
x=(33)23x=(33)23
Step 2.2.1.2
Apply the power rule and multiply exponents, (am)n=amn.
x=33(23)
x=33(23)
Step 2.2.2
Cancel the common factor of 3.
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Step 2.2.2.1
Cancel the common factor.
x=33(23)
Step 2.2.2.2
Rewrite the expression.
x=32
x=32
Step 2.2.3
Raise 3 to the power of 2.
x=9
x=9
x=9
 [x2  12  π  xdx ]