Algebra Examples

1 - r = - 5

$1 - r = - 5$

Step 1

Move all terms not containing

r

$r$ to the right side of the equation.

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Step 1.1

Subtract

1

$1$ from both sides of the equation.

- r = - 5 - 1

$- r = - 5 - 1$

Step 1.2

Subtract

1

$1$ from

- 5

$- 5$ .

- r = - 6

$- r = - 6$

- r = - 6

$- r = - 6$

Step 2

Divide each term in

- r = - 6

$- r = - 6$ by

- 1

$- 1$ and simplify.

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Step 2.1

Divide each term in

- r = - 6

$- r = - 6$ by

- 1

$- 1$ .

\frac{- r}{- 1} = \frac{- 6}{- 1}

$\frac{- r}{- 1} = \frac{- 6}{- 1}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Dividing two negative values results in a positive value.

\frac{r}{1} = \frac{- 6}{- 1}

$\frac{r}{1} = \frac{- 6}{- 1}$

Step 2.2.2

Divide

r

$r$ by

1

$1$ .

r = \frac{- 6}{- 1}

$r = \frac{- 6}{- 1}$

r = \frac{- 6}{- 1}

$r = \frac{- 6}{- 1}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide

- 6

$- 6$ by

- 1

$- 1$ .

r = 6

$r = 6$

r = 6

$r = 6$

r = 6

$r = 6$

1 - r = - 5

$1 - r = - 5$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$