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Algebra Examples
y=(x+2)(x-3)y=(x+2)(x−3)
Step 1
Step 1.1
Rewrite the equation in vertex form.
Step 1.1.1
Complete the square for (x+2)(x-3)(x+2)(x−3).
Step 1.1.1.1
Simplify the expression.
Step 1.1.1.1.1
Expand (x+2)(x-3)(x+2)(x−3) using the FOIL Method.
Step 1.1.1.1.1.1
Apply the distributive property.
x(x-3)+2(x-3)x(x−3)+2(x−3)
Step 1.1.1.1.1.2
Apply the distributive property.
x⋅x+x⋅-3+2(x-3)x⋅x+x⋅−3+2(x−3)
Step 1.1.1.1.1.3
Apply the distributive property.
x⋅x+x⋅-3+2x+2⋅-3x⋅x+x⋅−3+2x+2⋅−3
x⋅x+x⋅-3+2x+2⋅-3x⋅x+x⋅−3+2x+2⋅−3
Step 1.1.1.1.2
Simplify and combine like terms.
Step 1.1.1.1.2.1
Simplify each term.
Step 1.1.1.1.2.1.1
Multiply xx by xx.
x2+x⋅-3+2x+2⋅-3x2+x⋅−3+2x+2⋅−3
Step 1.1.1.1.2.1.2
Move -3−3 to the left of xx.
x2-3⋅x+2x+2⋅-3x2−3⋅x+2x+2⋅−3
Step 1.1.1.1.2.1.3
Multiply 22 by -3−3.
x2-3x+2x-6x2−3x+2x−6
x2-3x+2x-6x2−3x+2x−6
Step 1.1.1.1.2.2
Add -3x−3x and 2x2x.
x2-x-6x2−x−6
x2-x-6x2−x−6
x2-x-6x2−x−6
Step 1.1.1.2
Use the form ax2+bx+cax2+bx+c, to find the values of aa, bb, and cc.
a=1a=1
b=-1b=−1
c=-6c=−6
Step 1.1.1.3
Consider the vertex form of a parabola.
a(x+d)2+ea(x+d)2+e
Step 1.1.1.4
Find the value of dd using the formula d=b2ad=b2a.
Step 1.1.1.4.1
Substitute the values of aa and bb into the formula d=b2ad=b2a.
d=-12⋅1d=−12⋅1
Step 1.1.1.4.2
Simplify the right side.
Step 1.1.1.4.2.1
Cancel the common factor of -1−1 and 11.
Step 1.1.1.4.2.1.1
Rewrite -1−1 as -1(1)−1(1).
d=-1(1)2⋅1d=−1(1)2⋅1
Step 1.1.1.4.2.1.2
Cancel the common factor.
d=-1⋅12⋅1
Step 1.1.1.4.2.1.3
Rewrite the expression.
d=-12
d=-12
Step 1.1.1.4.2.2
Move the negative in front of the fraction.
d=-12
d=-12
d=-12
Step 1.1.1.5
Find the value of e using the formula e=c-b24a.
Step 1.1.1.5.1
Substitute the values of c, b and a into the formula e=c-b24a.
e=-6-(-1)24⋅1
Step 1.1.1.5.2
Simplify the right side.
Step 1.1.1.5.2.1
Simplify each term.
Step 1.1.1.5.2.1.1
Raise -1 to the power of 2.
e=-6-14⋅1
Step 1.1.1.5.2.1.2
Multiply 4 by 1.
e=-6-14
e=-6-14
Step 1.1.1.5.2.2
To write -6 as a fraction with a common denominator, multiply by 44.
e=-6⋅44-14
Step 1.1.1.5.2.3
Combine -6 and 44.
e=-6⋅44-14
Step 1.1.1.5.2.4
Combine the numerators over the common denominator.
e=-6⋅4-14
Step 1.1.1.5.2.5
Simplify the numerator.
Step 1.1.1.5.2.5.1
Multiply -6 by 4.
e=-24-14
Step 1.1.1.5.2.5.2
Subtract 1 from -24.
e=-254
e=-254
Step 1.1.1.5.2.6
Move the negative in front of the fraction.
e=-254
e=-254
e=-254
Step 1.1.1.6
Substitute the values of a, d, and e into the vertex form (x-12)2-254.
(x-12)2-254
(x-12)2-254
Step 1.1.2
Set y equal to the new right side.
y=(x-12)2-254
y=(x-12)2-254
Step 1.2
Use the vertex form, y=a(x-h)2+k, to determine the values of a, h, and k.
a=1
h=12
k=-254
Step 1.3
Since the value of a is positive, the parabola opens up.
Opens Up
Step 1.4
Find the vertex (h,k).
(12,-254)
Step 1.5
Find p, the distance from the vertex to the focus.
Step 1.5.1
Find the distance from the vertex to a focus of the parabola by using the following formula.
14a
Step 1.5.2
Substitute the value of a into the formula.
14⋅1
Step 1.5.3
Cancel the common factor of 1.
Step 1.5.3.1
Cancel the common factor.
14⋅1
Step 1.5.3.2
Rewrite the expression.
14
14
14
Step 1.6
Find the focus.
Step 1.6.1
The focus of a parabola can be found by adding p to the y-coordinate k if the parabola opens up or down.
(h,k+p)
Step 1.6.2
Substitute the known values of h, p, and k into the formula and simplify.
(12,-6)
(12,-6)
Step 1.7
Find the axis of symmetry by finding the line that passes through the vertex and the focus.
x=12
Step 1.8
Find the directrix.
Step 1.8.1
The directrix of a parabola is the horizontal line found by subtracting p from the y-coordinate k of the vertex if the parabola opens up or down.
y=k-p
Step 1.8.2
Substitute the known values of p and k into the formula and simplify.
y=-132
y=-132
Step 1.9
Use the properties of the parabola to analyze and graph the parabola.
Direction: Opens Up
Vertex: (12,-254)
Focus: (12,-6)
Axis of Symmetry: x=12
Directrix: y=-132
Direction: Opens Up
Vertex: (12,-254)
Focus: (12,-6)
Axis of Symmetry: x=12
Directrix: y=-132
Step 2
Step 2.1
Replace the variable x with -1 in the expression.
f(-1)=((-1)+2)((-1)-3)
Step 2.2
Simplify the result.
Step 2.2.1
Add -1 and 2.
f(-1)=1((-1)-3)
Step 2.2.2
Multiply (-1)-3 by 1.
f(-1)=(-1)-3
Step 2.2.3
Subtract 3 from -1.
f(-1)=-4
Step 2.2.4
The final answer is -4.
-4
-4
Step 2.3
The y value at x=-1 is -4.
y=-4
Step 2.4
Replace the variable x with -2 in the expression.
f(-2)=((-2)+2)((-2)-3)
Step 2.5
Simplify the result.
Step 2.5.1
Add -2 and 2.
f(-2)=0((-2)-3)
Step 2.5.2
Subtract 3 from -2.
f(-2)=0⋅-5
Step 2.5.3
Multiply 0 by -5.
f(-2)=0
Step 2.5.4
The final answer is 0.
0
0
Step 2.6
The y value at x=-2 is 0.
y=0
Step 2.7
Replace the variable x with 1 in the expression.
f(1)=((1)+2)((1)-3)
Step 2.8
Simplify the result.
Step 2.8.1
Add 1 and 2.
f(1)=3((1)-3)
Step 2.8.2
Subtract 3 from 1.
f(1)=3⋅-2
Step 2.8.3
Multiply 3 by -2.
f(1)=-6
Step 2.8.4
The final answer is -6.
-6
-6
Step 2.9
The y value at x=1 is -6.
y=-6
Step 2.10
Replace the variable x with 2 in the expression.
f(2)=((2)+2)((2)-3)
Step 2.11
Simplify the result.
Step 2.11.1
Add 2 and 2.
f(2)=4((2)-3)
Step 2.11.2
Subtract 3 from 2.
f(2)=4⋅-1
Step 2.11.3
Multiply 4 by -1.
f(2)=-4
Step 2.11.4
The final answer is -4.
-4
-4
Step 2.12
The y value at x=2 is -4.
y=-4
Step 2.13
Graph the parabola using its properties and the selected points.
xy-20-1-412-2541-62-4
xy-20-1-412-2541-62-4
Step 3
Graph the parabola using its properties and the selected points.
Direction: Opens Up
Vertex: (12,-254)
Focus: (12,-6)
Axis of Symmetry: x=12
Directrix: y=-132
xy-20-1-412-2541-62-4
Step 4
