Algebra Examples

7 (x + 1) = 21

$7 (x + 1) = 21$

Step 1

Divide each term in

7 (x + 1) = 21

$7 (x + 1) = 21$ by

7

$7$ and simplify.

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Step 1.1

Divide each term in

7 (x + 1) = 21

$7 (x + 1) = 21$ by

7

$7$ .

\frac{7 (x + 1)}{7} = \frac{21}{7}

$\frac{7 (x + 1)}{7} = \frac{21}{7}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

7

$7$ .

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Step 1.2.1.1

Cancel the common factor.

\frac{7 (x + 1)}{7} = \frac{21}{7}

$\frac{7 (x + 1)}{7} = \frac{21}{7}$

Step 1.2.1.2

Divide

x + 1

$x + 1$ by

1

$1$ .

x + 1 = \frac{21}{7}

$x + 1 = \frac{21}{7}$

x + 1 = \frac{21}{7}

$x + 1 = \frac{21}{7}$

x + 1 = \frac{21}{7}

$x + 1 = \frac{21}{7}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

21

$21$ by

7

$7$ .

x + 1 = 3

$x + 1 = 3$

x + 1 = 3

$x + 1 = 3$

x + 1 = 3

$x + 1 = 3$

Step 2

Move all terms not containing

x

$x$ to the right side of the equation.

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Step 2.1

Subtract

1

$1$ from both sides of the equation.

x = 3 - 1

$x = 3 - 1$

Step 2.2

Subtract

1

$1$ from

3

$3$ .

x = 2

$x = 2$

x = 2

$x = 2$

7 (x + 1) = 21

$7 (x + 1) = 21$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$