Algebra Examples

Expand Using the Binomial Theorem (1-x)^3
(1-x)3
Step 1
Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=nk=0nCk(an-kbk).
3k=03!(3-k)!k!(1)3-k(-x)k
Step 2
Expand the summation.
3!(3-0)!0!(1)3-0(-x)0+3!(3-1)!1!(1)3-1(-x)1+3!(3-2)!2!(1)3-2(-x)2+3!(3-3)!3!(1)3-3(-x)3
Step 3
Simplify the exponents for each term of the expansion.
1(1)3(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4
Simplify each term.
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Step 4.1
Multiply 1 by (1)3 by adding the exponents.
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Step 4.1.1
Multiply 1 by (1)3.
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Step 4.1.1.1
Raise 1 to the power of 1.
11(1)3(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.1.1.2
Use the power rule aman=am+n to combine exponents.
11+3(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
11+3(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.1.2
Add 1 and 3.
14(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
14(-x)0+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.2
Simplify 14(-x)0.
14+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.3
One to any power is one.
1+3(1)2(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.4
One to any power is one.
1+31(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.5
Multiply 3 by 1.
1+3(-x)1+3(1)1(-x)2+1(1)0(-x)3
Step 4.6
Simplify.
1+3(-x)+3(1)1(-x)2+1(1)0(-x)3
Step 4.7
Multiply -1 by 3.
1-3x+3(1)1(-x)2+1(1)0(-x)3
Step 4.8
Evaluate the exponent.
1-3x+31(-x)2+1(1)0(-x)3
Step 4.9
Multiply 3 by 1.
1-3x+3(-x)2+1(1)0(-x)3
Step 4.10
Apply the product rule to -x.
1-3x+3((-1)2x2)+1(1)0(-x)3
Step 4.11
Raise -1 to the power of 2.
1-3x+3(1x2)+1(1)0(-x)3
Step 4.12
Multiply x2 by 1.
1-3x+3x2+1(1)0(-x)3
Step 4.13
Multiply 1 by (1)0 by adding the exponents.
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Step 4.13.1
Multiply 1 by (1)0.
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Step 4.13.1.1
Raise 1 to the power of 1.
1-3x+3x2+11(1)0(-x)3
Step 4.13.1.2
Use the power rule aman=am+n to combine exponents.
1-3x+3x2+11+0(-x)3
1-3x+3x2+11+0(-x)3
Step 4.13.2
Add 1 and 0.
1-3x+3x2+11(-x)3
1-3x+3x2+11(-x)3
Step 4.14
Simplify 11(-x)3.
1-3x+3x2+(-x)3
Step 4.15
Apply the product rule to -x.
1-3x+3x2+(-1)3x3
Step 4.16
Raise -1 to the power of 3.
1-3x+3x2-x3
1-3x+3x2-x3
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