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Algebra Examples
(1-x)3
Step 1
Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an-kbk).
3∑k=03!(3-k)!k!⋅(1)3-k⋅(-x)k
Step 2
Expand the summation.
3!(3-0)!0!⋅(1)3-0⋅(-x)0+3!(3-1)!1!⋅(1)3-1⋅(-x)1+3!(3-2)!2!⋅(1)3-2⋅(-x)2+3!(3-3)!3!⋅(1)3-3⋅(-x)3
Step 3
Simplify the exponents for each term of the expansion.
1⋅(1)3⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4
Step 4.1
Multiply 1 by (1)3 by adding the exponents.
Step 4.1.1
Multiply 1 by (1)3.
Step 4.1.1.1
Raise 1 to the power of 1.
11⋅(1)3⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.1.1.2
Use the power rule aman=am+n to combine exponents.
11+3⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
11+3⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.1.2
Add 1 and 3.
14⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
14⋅(-x)0+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.2
Simplify 14⋅(-x)0.
14+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.3
One to any power is one.
1+3⋅(1)2⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.4
One to any power is one.
1+3⋅1⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.5
Multiply 3 by 1.
1+3⋅(-x)1+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.6
Simplify.
1+3⋅(-x)+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.7
Multiply -1 by 3.
1-3x+3⋅(1)1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.8
Evaluate the exponent.
1-3x+3⋅1⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.9
Multiply 3 by 1.
1-3x+3⋅(-x)2+1⋅(1)0⋅(-x)3
Step 4.10
Apply the product rule to -x.
1-3x+3⋅((-1)2x2)+1⋅(1)0⋅(-x)3
Step 4.11
Raise -1 to the power of 2.
1-3x+3⋅(1x2)+1⋅(1)0⋅(-x)3
Step 4.12
Multiply x2 by 1.
1-3x+3⋅x2+1⋅(1)0⋅(-x)3
Step 4.13
Multiply 1 by (1)0 by adding the exponents.
Step 4.13.1
Multiply 1 by (1)0.
Step 4.13.1.1
Raise 1 to the power of 1.
1-3x+3x2+11⋅(1)0⋅(-x)3
Step 4.13.1.2
Use the power rule aman=am+n to combine exponents.
1-3x+3x2+11+0⋅(-x)3
1-3x+3x2+11+0⋅(-x)3
Step 4.13.2
Add 1 and 0.
1-3x+3x2+11⋅(-x)3
1-3x+3x2+11⋅(-x)3
Step 4.14
Simplify 11⋅(-x)3.
1-3x+3x2+(-x)3
Step 4.15
Apply the product rule to -x.
1-3x+3x2+(-1)3x3
Step 4.16
Raise -1 to the power of 3.
1-3x+3x2-x3
1-3x+3x2-x3