Algebra Examples

Solve for x 2/3x+15=17
23x+15=1723x+15=17
Step 1
Combine 2323 and xx.
2x3+15=172x3+15=17
Step 2
Move all terms not containing xx to the right side of the equation.
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Step 2.1
Subtract 1515 from both sides of the equation.
2x3=17-152x3=1715
Step 2.2
Subtract 1515 from 1717.
2x3=22x3=2
2x3=22x3=2
Step 3
Multiply both sides of the equation by 3232.
322x3=322322x3=322
Step 4
Simplify both sides of the equation.
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Step 4.1
Simplify the left side.
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Step 4.1.1
Simplify 322x3322x3.
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Step 4.1.1.1
Cancel the common factor of 33.
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Step 4.1.1.1.1
Cancel the common factor.
322x3=322
Step 4.1.1.1.2
Rewrite the expression.
12(2x)=322
12(2x)=322
Step 4.1.1.2
Cancel the common factor of 2.
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Step 4.1.1.2.1
Factor 2 out of 2x.
12(2(x))=322
Step 4.1.1.2.2
Cancel the common factor.
12(2x)=322
Step 4.1.1.2.3
Rewrite the expression.
x=322
x=322
x=322
x=322
Step 4.2
Simplify the right side.
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Step 4.2.1
Cancel the common factor of 2.
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Step 4.2.1.1
Cancel the common factor.
x=322
Step 4.2.1.2
Rewrite the expression.
x=3
x=3
x=3
x=3
 [x2  12  π  xdx ]