Algebra Examples

5 x + 2 = 2 x - 10

$5 x + 2 = 2 x - 10$

Step 1

Move all terms containing

x

$x$ to the left side of the equation.

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Step 1.1

Subtract

2 x

$2 x$ from both sides of the equation.

5 x + 2 - 2 x = - 10

$5 x + 2 - 2 x = - 10$

Step 1.2

Subtract

2 x

$2 x$ from

5 x

$5 x$ .

3 x + 2 = - 10

$3 x + 2 = - 10$

3 x + 2 = - 10

$3 x + 2 = - 10$

Step 2

Move all terms not containing

x

$x$ to the right side of the equation.

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Step 2.1

Subtract

2

$2$ from both sides of the equation.

3 x = - 10 - 2

$3 x = - 10 - 2$

Step 2.2

Subtract

2

$2$ from

- 10

$- 10$ .

3 x = - 12

$3 x = - 12$

3 x = - 12

$3 x = - 12$

Step 3

Divide each term in

3 x = - 12

$3 x = - 12$ by

3

$3$ and simplify.

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Step 3.1

Divide each term in

3 x = - 12

$3 x = - 12$ by

3

$3$ .

\frac{3 x}{3} = \frac{- 12}{3}

$\frac{3 x}{3} = \frac{- 12}{3}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

3

$3$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 12}{3}$

Step 3.2.1.2

Divide

$x$ by

$1$ .

$x = \frac{- 12}{3}$

$x = \frac{- 12}{3}$

$x = \frac{- 12}{3}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide

$- 12$ by

$3$ .

$x = - 4$

$x = - 4$

$x = - 4$

$5 x + 2 = 2 x - 10$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$