Algebra Examples

Solve Using the Quadratic Formula 6x^2+5x-6=0
6x2+5x-6=06x2+5x6=0
Step 1
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2ab±b24(ac)2a
Step 2
Substitute the values a=6a=6, b=5b=5, and c=-6c=6 into the quadratic formula and solve for xx.
-5±52-4(6-6)265±524(66)26
Step 3
Simplify.
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Step 3.1
Simplify the numerator.
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Step 3.1.1
Raise 55 to the power of 22.
x=-5±25-46-626x=5±2546626
Step 3.1.2
Multiply -46-6466.
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Step 3.1.2.1
Multiply -44 by 66.
x=-5±25-24-626x=5±2524626
Step 3.1.2.2
Multiply -2424 by -66.
x=-5±25+14426x=5±25+14426
x=-5±25+14426x=5±25+14426
Step 3.1.3
Add 2525 and 144144.
x=-5±16926x=5±16926
Step 3.1.4
Rewrite 169169 as 132132.
x=-5±13226x=5±13226
Step 3.1.5
Pull terms out from under the radical, assuming positive real numbers.
x=-5±1326x=5±1326
x=-5±1326x=5±1326
Step 3.2
Multiply 22 by 66.
x=-5±1312x=5±1312
x=-5±1312x=5±1312
Step 4
The final answer is the combination of both solutions.
x=23,-32x=23,32
 [x2  12  π  xdx ]  x2  12  π  xdx