Algebra Examples

$3 (2 x + 5) = 39$

Step 1

Divide each term in $3 (2 x + 5) = 39$ by $3$ and simplify.

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Step 1.1

Divide each term in $3 (2 x + 5) = 39$ by $3$ .

$\frac{3 (2 x + 5)}{3} = \frac{39}{3}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $3$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{3 (2 x + 5)}{3} = \frac{39}{3}$

Step 1.2.1.2

Divide $2 x + 5$ by $1$ .

$2 x + 5 = \frac{39}{3}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide $39$ by $3$ .

$2 x + 5 = 13$

Step 2

Move all terms not containing $x$ to the right side of the equation.

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Step 2.1

Subtract $5$ from both sides of the equation.

$2 x = 13 - 5$

Step 2.2

Subtract $5$ from $13$ .

$2 x = 8$

Step 3

Divide each term in $2 x = 8$ by $2$ and simplify.

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Step 3.1

Divide each term in $2 x = 8$ by $2$ .

$\frac{2 x}{2} = \frac{8}{2}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $2$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{8}{2}$

Step 3.2.1.2

Divide $x$ by $1$ .

$x = \frac{8}{2}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide $8$ by $2$ .

$x = 4$