Algebra Examples

$2 y + 3 = 3 (y + 7)$

Step 1

Simplify $3 (y + 7)$ .

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Step 1.1

Rewrite.

$2 y + 3 = 0 + 0 + 3 (y + 7)$

Step 1.2

Simplify by adding zeros.

$2 y + 3 = 3 (y + 7)$

Step 1.3

Apply the distributive property.

$2 y + 3 = 3 y + 3 \cdot 7$

Step 1.4

Multiply $3$ by $7$ .

$2 y + 3 = 3 y + 21$

Step 2

Move all terms containing $y$ to the left side of the equation.

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Step 2.1

Subtract $3 y$ from both sides of the equation.

$2 y + 3 - 3 y = 21$

Step 2.2

Subtract $3 y$ from $2 y$ .

$- y + 3 = 21$

Step 3

Move all terms not containing $y$ to the right side of the equation.

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Step 3.1

Subtract $3$ from both sides of the equation.

$- y = 21 - 3$

Step 3.2

Subtract $3$ from $21$ .

$- y = 18$

Step 4

Divide each term in $- y = 18$ by $- 1$ and simplify.

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Step 4.1

Divide each term in $- y = 18$ by $- 1$ .

$\frac{- y}{- 1} = \frac{18}{- 1}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{18}{- 1}$

Step 4.2.2

Divide $y$ by $1$ .

$y = \frac{18}{- 1}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $18$ by $- 1$ .

$y = - 18$