Algebra Examples

$y = (x - 3) (x + 4)$

Step 1

Find the properties of the given parabola.

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Step 1.1

Rewrite the equation in vertex form.

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Step 1.1.1

Complete the square for $(x - 3) (x + 4)$ .

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Step 1.1.1.1

Simplify the expression.

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Step 1.1.1.1.1

Expand $(x - 3) (x + 4)$ using the FOIL Method.

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Step 1.1.1.1.1.1

Apply the distributive property.

$x (x + 4) - 3 (x + 4)$

Step 1.1.1.1.1.2

Apply the distributive property.

$x \cdot x + x \cdot 4 - 3 (x + 4)$

Step 1.1.1.1.1.3

Apply the distributive property.

$x \cdot x + x \cdot 4 - 3 x - 3 \cdot 4$

Step 1.1.1.1.2

Simplify and combine like terms.

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Step 1.1.1.1.2.1

Simplify each term.

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Step 1.1.1.1.2.1.1

Multiply $x$ by $x$ .

$x^{2} + x \cdot 4 - 3 x - 3 \cdot 4$

Step 1.1.1.1.2.1.2

Move $4$ to the left of $x$ .

$x^{2} + 4 \cdot x - 3 x - 3 \cdot 4$

Step 1.1.1.1.2.1.3

Multiply $- 3$ by $4$ .

$x^{2} + 4 x - 3 x - 12$

Step 1.1.1.1.2.2

Subtract $3 x$ from $4 x$ .

$x^{2} + x - 12$

Step 1.1.1.2

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 1$

$c = - 12$

Step 1.1.1.3

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.1.1.4

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 1.1.1.4.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{1}{2 \cdot 1}$

Step 1.1.1.4.2

Cancel the common factor of $1$ .

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Step 1.1.1.4.2.1

Cancel the common factor.

$d = \frac{1}{2 \cdot 1}$

Step 1.1.1.4.2.2

Rewrite the expression.

$d = \frac{1}{2}$

Step 1.1.1.5

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 1.1.1.5.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 12 - \frac{1^{2}}{4 \cdot 1}$

Step 1.1.1.5.2

Simplify the right side.

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Step 1.1.1.5.2.1

Simplify each term.

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Step 1.1.1.5.2.1.1

One to any power is one.

$e = - 12 - \frac{1}{4 \cdot 1}$

Step 1.1.1.5.2.1.2

Multiply $4$ by $1$ .

$e = - 12 - \frac{1}{4}$

Step 1.1.1.5.2.2

To write $- 12$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = - 12 \cdot \frac{4}{4} - \frac{1}{4}$

Step 1.1.1.5.2.3

Combine $- 12$ and $\frac{4}{4}$ .

$e = \frac{- 12 \cdot 4}{4} - \frac{1}{4}$

Step 1.1.1.5.2.4

Combine the numerators over the common denominator.

$e = \frac{- 12 \cdot 4 - 1}{4}$

Step 1.1.1.5.2.5

Simplify the numerator.

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Step 1.1.1.5.2.5.1

Multiply $- 12$ by $4$ .

$e = \frac{- 48 - 1}{4}$

Step 1.1.1.5.2.5.2

Subtract $1$ from $- 48$ .

$e = \frac{- 49}{4}$

Step 1.1.1.5.2.6

Move the negative in front of the fraction.

$e = - \frac{49}{4}$

Step 1.1.1.6

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + \frac{1}{2})}^{2} - \frac{49}{4}$ .

${(x + \frac{1}{2})}^{2} - \frac{49}{4}$

Step 1.1.2

Set $y$ equal to the new right side.

$y = {(x + \frac{1}{2})}^{2} - \frac{49}{4}$

Step 1.2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = - \frac{1}{2}$

$k = - \frac{49}{4}$

Step 1.3

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Step 1.4

Find the vertex $(h, k)$ .

$(- \frac{1}{2}, - \frac{49}{4})$

Step 1.5

Find $p$ , the distance from the vertex to the focus.

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Step 1.5.1

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Step 1.5.2

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Step 1.5.3

Cancel the common factor of $1$ .

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Step 1.5.3.1

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Step 1.5.3.2

Rewrite the expression.

$\frac{1}{4}$

Step 1.6

Find the focus.

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Step 1.6.1

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Step 1.6.2

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- \frac{1}{2}, - 12)$

Step 1.7

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - \frac{1}{2}$

Step 1.8

Find the directrix.

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Step 1.8.1

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Step 1.8.2

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{25}{2}$

Step 1.9

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(- \frac{1}{2}, - \frac{49}{4})$

Focus: $(- \frac{1}{2}, - 12)$

Axis of Symmetry: $x = - \frac{1}{2}$

Directrix: $y = - \frac{25}{2}$

Direction: Opens Up

Vertex: $(- \frac{1}{2}, - \frac{49}{4})$

Focus: $(- \frac{1}{2}, - 12)$

Axis of Symmetry: $x = - \frac{1}{2}$

Directrix: $y = - \frac{25}{2}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

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Step 2.1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = ((- 1) - 3) ((- 1) + 4)$

Step 2.2

Simplify the result.

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Step 2.2.1

Subtract $3$ from $- 1$ .

$f (- 1) = - 4 ((- 1) + 4)$

Step 2.2.2

Add $- 1$ and $4$ .

$f (- 1) = - 4 \cdot 3$

Step 2.2.3

Multiply $- 4$ by $3$ .

$f (- 1) = - 12$

Step 2.2.4

The final answer is $- 12$ .

$- 12$

Step 2.3

The $y$ value at $x = - 1$ is $- 12$ .

$y = - 12$

Step 2.4

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = ((- 2) - 3) ((- 2) + 4)$

Step 2.5

Simplify the result.

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Step 2.5.1

Subtract $3$ from $- 2$ .

$f (- 2) = - 5 ((- 2) + 4)$

Step 2.5.2

Add $- 2$ and $4$ .

$f (- 2) = - 5 \cdot 2$

Step 2.5.3

Multiply $- 5$ by $2$ .

$f (- 2) = - 10$

Step 2.5.4

The final answer is $- 10$ .

$- 10$

Step 2.6

The $y$ value at $x = - 2$ is $- 10$ .

$y = - 10$

Step 2.7

Replace the variable $x$ with $1$ in the expression.

$f (1) = ((1) - 3) ((1) + 4)$

Step 2.8

Simplify the result.

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Step 2.8.1

Subtract $3$ from $1$ .

$f (1) = - 2 ((1) + 4)$

Step 2.8.2

Add $1$ and $4$ .

$f (1) = - 2 \cdot 5$

Step 2.8.3

Multiply $- 2$ by $5$ .

$f (1) = - 10$

Step 2.8.4

The final answer is $- 10$ .

$- 10$

Step 2.9

The $y$ value at $x = 1$ is $- 10$ .

$y = - 10$

Step 2.10

Replace the variable $x$ with $2$ in the expression.

$f (2) = ((2) - 3) ((2) + 4)$

Step 2.11

Simplify the result.

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Step 2.11.1

Subtract $3$ from $2$ .

$f (2) = - 1 ((2) + 4)$

Step 2.11.2

Add $2$ and $4$ .

$f (2) = - 1 \cdot 6$

Step 2.11.3

Multiply $- 1$ by $6$ .

$f (2) = - 6$

Step 2.11.4

The final answer is $- 6$ .

$- 6$

Step 2.12

The $y$ value at $x = 2$ is $- 6$ .

$y = - 6$

Step 2.13

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 2 & - 10 \\ - 1 & - 12 \\ - \frac{1}{2} & - \frac{49}{4} \\ 1 & - 10 \\ 2 & - 6 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(- \frac{1}{2}, - \frac{49}{4})$

Focus: $(- \frac{1}{2}, - 12)$

Axis of Symmetry: $x = - \frac{1}{2}$

Directrix: $y = - \frac{25}{2}$

$\begin{array}{c} x & y \\ - 2 & - 10 \\ - 1 & - 12 \\ - \frac{1}{2} & - \frac{49}{4} \\ 1 & - 10 \\ 2 & - 6 \end{array}$

Step 4