Algebra Examples

$36 v^{2} - 25$

Step 1

Rewrite $36 v^{2}$ as ${(6 v)}^{2}$ .

${(6 v)}^{2} - 25$

Step 2

Rewrite $25$ as $5^{2}$ .

${(6 v)}^{2} - 5^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 6 v$ and $b = 5$ .

$(6 v + 5) (6 v - 5)$