Algebra Examples

$x - y = - 8$

Step 1

Solve for

$y$ .

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Step 1.1

Subtract

$x$ from both sides of the equation.

$- y = - 8 - x$

Step 1.2

Divide each term in

$- y = - 8 - x$ by

$- 1$ and simplify.

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Step 1.2.1

Divide each term in

$- y = - 8 - x$ by

$- 1$ .

$\frac{- y}{- 1} = \frac{- 8}{- 1} + \frac{- x}{- 1}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 8}{- 1} + \frac{- x}{- 1}$

Step 1.2.2.2

Divide

$y$ by

$1$ .

$y = \frac{- 8}{- 1} + \frac{- x}{- 1}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Divide

$- 8$ by

$- 1$ .

$y = 8 + \frac{- x}{- 1}$

Step 1.2.3.1.2

Dividing two negative values results in a positive value.

$y = 8 + \frac{x}{1}$

Step 1.2.3.1.3

Divide

$x$ by

$1$ .

$y = 8 + x$

Step 2

Rewrite in slope-intercept form.

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Step 2.1

The slope-intercept form is

$y = m x + b$ , where

$m$ is the slope and

$b$ is the y-intercept.

$y = m x + b$

Step 2.2

Reorder

$8$ and

$x$ .

$y = x + 8$

Step 3

Use the slope-intercept form to find the slope and y-intercept.

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Step 3.1

Find the values of

$m$ and

$b$ using the form

$y = m x + b$ .

$m = 1$

$b = 8$

Step 3.2

The slope of the line is the value of

$m$ , and the y-intercept is the value of

$b$ .

Slope:

$1$

y-intercept:

$(0, 8)$

Slope:

$1$

y-intercept:

$(0, 8)$

Step 4

Any line can be graphed using two points. Select two

$x$ values, and plug them into the equation to find the corresponding

$y$ values.

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Step 4.1

Reorder

$8$ and

$x$ .

$y = x + 8$

Step 4.2

Create a table of the

$x$ and

$y$ values.

$\begin{array}{c} x & y \\ 0 & 8 \\ 1 & 9 \end{array}$

Step 5

Graph the line using the slope and the y-intercept, or the points.

Slope:

$1$

y-intercept:

$(0, 8)$

$\begin{array}{c} x & y \\ 0 & 8 \\ 1 & 9 \end{array}$

Step 6