Algebra Examples

Solve by Factoring x^2-8x+15=0
x2-8x+15=0
Step 1
Factor x2-8x+15 using the AC method.
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Step 1.1
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 15 and whose sum is -8.
-5,-3
Step 1.2
Write the factored form using these integers.
(x-5)(x-3)=0
(x-5)(x-3)=0
Step 2
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-5=0
x-3=0
Step 3
Set x-5 equal to 0 and solve for x.
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Step 3.1
Set x-5 equal to 0.
x-5=0
Step 3.2
Add 5 to both sides of the equation.
x=5
x=5
Step 4
Set x-3 equal to 0 and solve for x.
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Step 4.1
Set x-3 equal to 0.
x-3=0
Step 4.2
Add 3 to both sides of the equation.
x=3
x=3
Step 5
The final solution is all the values that make (x-5)(x-3)=0 true.
x=5,3
 [x2  12  π  xdx ]