Algebra Examples

$24 = 6 (- x - 3)$

Step 1

Rewrite the equation as

$6 (- x - 3) = 24$ .

$6 (- x - 3) = 24$

Step 2

Divide each term in

$6 (- x - 3) = 24$ by

$6$ and simplify.

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Step 2.1

Divide each term in

$6 (- x - 3) = 24$ by

$6$ .

$\frac{6 (- x - 3)}{6} = \frac{24}{6}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of

$6$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{6 (- x - 3)}{6} = \frac{24}{6}$

Step 2.2.1.2

Divide

$- x - 3$ by

$1$ .

$- x - 3 = \frac{24}{6}$

$- x - 3 = \frac{24}{6}$

$- x - 3 = \frac{24}{6}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide

$24$ by

$6$ .

$- x - 3 = 4$

$- x - 3 = 4$

$- x - 3 = 4$

Step 3

Move all terms not containing

$x$ to the right side of the equation.

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Step 3.1

Add

$3$ to both sides of the equation.

$- x = 4 + 3$

Step 3.2

Add

$4$ and

$3$ .

$- x = 7$

$- x = 7$

Step 4

Divide each term in

$- x = 7$ by

$- 1$ and simplify.

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Step 4.1

Divide each term in

$- x = 7$ by

$- 1$ .

$\frac{- x}{- 1} = \frac{7}{- 1}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{7}{- 1}$

Step 4.2.2

Divide

$x$ by

$1$ .

$x = \frac{7}{- 1}$

$x = \frac{7}{- 1}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide

$7$ by

$- 1$ .

$x = - 7$

$x = - 7$

$x = - 7$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$