Algebra Examples

$\frac{1}{12} x^{2} - \frac{1}{6} x = 1$

Step 1

Move all terms to the left side of the equation and simplify.

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Step 1.1

Simplify the left side.

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Step 1.1.1

Simplify each term.

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Step 1.1.1.1

Combine $\frac{1}{12}$ and $x^{2}$ .

$\frac{x^{2}}{12} - \frac{1}{6} x = 1$

Step 1.1.1.2

Combine $x$ and $\frac{1}{6}$ .

$\frac{x^{2}}{12} - \frac{x}{6} = 1$

Step 1.2

Subtract $1$ from both sides of the equation.

$\frac{x^{2}}{12} - \frac{x}{6} - 1 = 0$

Step 2

Multiply through by the least common denominator $12$ , then simplify.

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Step 2.1

Apply the distributive property.

$12 (\frac{x^{2}}{12}) + 12 (- \frac{x}{6}) + 12 \cdot - 1 = 0$

Step 2.2

Simplify.

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Step 2.2.1

Cancel the common factor of $12$ .

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Step 2.2.1.1

Cancel the common factor.

$12 (\frac{x^{2}}{12}) + 12 (- \frac{x}{6}) + 12 \cdot - 1 = 0$

Step 2.2.1.2

Rewrite the expression.

$x^{2} + 12 (- \frac{x}{6}) + 12 \cdot - 1 = 0$

Step 2.2.2

Cancel the common factor of $6$ .

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Step 2.2.2.1

Move the leading negative in $- \frac{x}{6}$ into the numerator.

$x^{2} + 12 (\frac{- x}{6}) + 12 \cdot - 1 = 0$

Step 2.2.2.2

Factor $6$ out of $12$ .

$x^{2} + 6 (2) (\frac{- x}{6}) + 12 \cdot - 1 = 0$

Step 2.2.2.3

Cancel the common factor.

$x^{2} + 6 \cdot (2 (\frac{- x}{6})) + 12 \cdot - 1 = 0$

Step 2.2.2.4

Rewrite the expression.

$x^{2} + 2 (- x) + 12 \cdot - 1 = 0$

Step 2.2.3

Multiply $- 1$ by $2$ .

$x^{2} - 2 x + 12 \cdot - 1 = 0$

Step 2.2.4

Multiply $12$ by $- 1$ .

$x^{2} - 2 x - 12 = 0$

Step 3

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 4

Substitute the values $a = 1$ , $b = - 2$ , and $c = - 12$ into the quadratic formula and solve for $x$ .

$\frac{2 \pm \sqrt{{(- 2)}^{2} - 4 \cdot (1 \cdot - 12)}}{2 \cdot 1}$

Step 5

Simplify.

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Step 5.1

Simplify the numerator.

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Step 5.1.1

Raise $- 2$ to the power of $2$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot 1 \cdot - 12}}{2 \cdot 1}$

Step 5.1.2

Multiply $- 4 \cdot 1 \cdot - 12$ .

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Step 5.1.2.1

Multiply $- 4$ by $1$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot - 12}}{2 \cdot 1}$

Step 5.1.2.2

Multiply $- 4$ by $- 12$ .

$x = \frac{2 \pm \sqrt{4 + 48}}{2 \cdot 1}$

Step 5.1.3

Add $4$ and $48$ .

$x = \frac{2 \pm \sqrt{52}}{2 \cdot 1}$

Step 5.1.4

Rewrite $52$ as $2^{2} \cdot 13$ .

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Step 5.1.4.1

Factor $4$ out of $52$ .

$x = \frac{2 \pm \sqrt{4 (13)}}{2 \cdot 1}$

Step 5.1.4.2

Rewrite $4$ as $2^{2}$ .

$x = \frac{2 \pm \sqrt{2^{2} \cdot 13}}{2 \cdot 1}$

Step 5.1.5

Pull terms out from under the radical.

$x = \frac{2 \pm 2 \sqrt{13}}{2 \cdot 1}$

Step 5.2

Multiply $2$ by $1$ .

$x = \frac{2 \pm 2 \sqrt{13}}{2}$

Step 5.3

Simplify $\frac{2 \pm 2 \sqrt{13}}{2}$ .

$x = 1 \pm \sqrt{13}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = 1 \pm \sqrt{13}$

Decimal Form:

$x = 4.60555127 \dots, - 2.60555127 \dots$