Algebra Examples

$26 + 6 b \geq 2 (3 b + 4)$

Step 1

Simplify $2 (3 b + 4)$ .

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Step 1.1

Rewrite.

$26 + 6 b \geq 0 + 0 + 2 (3 b + 4)$

Step 1.2

Simplify by adding zeros.

$26 + 6 b \geq 2 (3 b + 4)$

Step 1.3

Apply the distributive property.

$26 + 6 b \geq 2 (3 b) + 2 \cdot 4$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $3$ by $2$ .

$26 + 6 b \geq 6 b + 2 \cdot 4$

Step 1.4.2

Multiply $2$ by $4$ .

$26 + 6 b \geq 6 b + 8$

Step 2

Move all terms containing $b$ to the left side of the inequality.

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Step 2.1

Subtract $6 b$ from both sides of the inequality.

$26 + 6 b - 6 b \geq 8$

Step 2.2

Combine the opposite terms in $26 + 6 b - 6 b$ .

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Step 2.2.1

Subtract $6 b$ from $6 b$ .

$26 + 0 \geq 8$

Step 2.2.2

Add $26$ and $0$ .

$26 \geq 8$

Step 3

Since $26 \geq 8$ , the inequality will always be true.

Always true

Step 4