Algebra Examples

Graph y = log base 3 of x
y=log3(x)
Step 1
Find the asymptotes.
Tap for more steps...
Step 1.1
Set the argument of the logarithm equal to zero.
x=0
Step 1.2
The vertical asymptote occurs at x=0.
Vertical Asymptote: x=0
Vertical Asymptote: x=0
Step 2
Find the point at x=1.
Tap for more steps...
Step 2.1
Replace the variable x with 1 in the expression.
f(1)=log3(1)
Step 2.2
Simplify the result.
Tap for more steps...
Step 2.2.1
Logarithm base 3 of 1 is 0.
f(1)=0
Step 2.2.2
The final answer is 0.
0
0
Step 2.3
Convert 0 to decimal.
y=0
y=0
Step 3
Find the point at x=3.
Tap for more steps...
Step 3.1
Replace the variable x with 3 in the expression.
f(3)=log3(3)
Step 3.2
Simplify the result.
Tap for more steps...
Step 3.2.1
Logarithm base 3 of 3 is 1.
f(3)=1
Step 3.2.2
The final answer is 1.
1
1
Step 3.3
Convert 1 to decimal.
y=1
y=1
Step 4
Find the point at x=9.
Tap for more steps...
Step 4.1
Replace the variable x with 9 in the expression.
f(9)=log3(9)
Step 4.2
Simplify the result.
Tap for more steps...
Step 4.2.1
Logarithm base 3 of 9 is 2.
Tap for more steps...
Step 4.2.1.1
Rewrite as an equation.
log3(9)=x
Step 4.2.1.2
Rewrite log3(9)=x in exponential form using the definition of a logarithm. If x and b are positive real numbers and b does not equal 1, then logb(x)=y is equivalent to by=x.
3x=9
Step 4.2.1.3
Create equivalent expressions in the equation that all have equal bases.
3x=32
Step 4.2.1.4
Since the bases are the same, the two expressions are only equal if the exponents are also equal.
x=2
Step 4.2.1.5
The variable x is equal to 2.
f(9)=2
f(9)=2
Step 4.2.2
The final answer is 2.
2
2
Step 4.3
Convert 2 to decimal.
y=2
y=2
Step 5
The log function can be graphed using the vertical asymptote at x=0 and the points (1,0),(3,1),(9,2).
Vertical Asymptote: x=0
xy103192
Step 6
image of graph
y=log3x
(
(
)
)
|
|
[
[
]
]
7
7
8
8
9
9
4
4
5
5
6
6
/
/
^
^
×
×
>
>
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
π
π
,
,
0
0
.
.
%
%
=
=
 [x2  12  π  xdx ]