Algebra Examples

Find the Perpendicular Line Through (9,-8) , perpendicular to x+y=7
Through (9,-8) , perpendicular to x+y=7
Step 1
Subtract x from both sides of the equation.
y=7-x
Step 2
Find the slope when y=7-x.
Tap for more steps...
Step 2.1
Rewrite in slope-intercept form.
Tap for more steps...
Step 2.1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 2.1.2
Reorder 7 and -x.
y=-x+7
y=-x+7
Step 2.2
Using the slope-intercept form, the slope is -1.
m=-1
m=-1
Step 3
The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.
mperpendicular=-1-1
Step 4
Simplify -1-1 to find the slope of the perpendicular line.
Tap for more steps...
Step 4.1
Divide 1 by -1.
mperpendicular=1
Step 4.2
Multiply -1 by -1.
mperpendicular=1
mperpendicular=1
Step 5
Find the equation of the perpendicular line using the point-slope formula.
Tap for more steps...
Step 5.1
Use the slope 1 and a given point (9,-8) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(-8)=1(x-(9))
Step 5.2
Simplify the equation and keep it in point-slope form.
y+8=1(x-9)
y+8=1(x-9)
Step 6
Solve for y.
Tap for more steps...
Step 6.1
Multiply x-9 by 1.
y+8=x-9
Step 6.2
Move all terms not containing y to the right side of the equation.
Tap for more steps...
Step 6.2.1
Subtract 8 from both sides of the equation.
y=x-9-8
Step 6.2.2
Subtract 8 from -9.
y=x-17
y=x-17
y=x-17
Step 7
 [x2  12  π  xdx ]