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Algebra Examples
A line is perpendicular to y=3x-8 and intersects the point (6,1)
Step 1
Write the problem as a mathematical expression.
y=3x-8 , (6,1)
Step 2
Step 2.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 2.2
Using the slope-intercept form, the slope is 3.
m=3
m=3
Step 3
The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.
mperpendicular=-13
Step 4
Step 4.1
Use the slope -13 and a given point (6,1) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(1)=-13⋅(x-(6))
Step 4.2
Simplify the equation and keep it in point-slope form.
y-1=-13⋅(x-6)
y-1=-13⋅(x-6)
Step 5
Step 5.1
Solve for y.
Step 5.1.1
Simplify -13⋅(x-6).
Step 5.1.1.1
Rewrite.
y-1=0+0-13⋅(x-6)
Step 5.1.1.2
Simplify by adding zeros.
y-1=-13⋅(x-6)
Step 5.1.1.3
Apply the distributive property.
y-1=-13x-13⋅-6
Step 5.1.1.4
Combine x and 13.
y-1=-x3-13⋅-6
Step 5.1.1.5
Cancel the common factor of 3.
Step 5.1.1.5.1
Move the leading negative in -13 into the numerator.
y-1=-x3+-13⋅-6
Step 5.1.1.5.2
Factor 3 out of -6.
y-1=-x3+-13⋅(3(-2))
Step 5.1.1.5.3
Cancel the common factor.
y-1=-x3+-13⋅(3⋅-2)
Step 5.1.1.5.4
Rewrite the expression.
y-1=-x3-1⋅-2
y-1=-x3-1⋅-2
Step 5.1.1.6
Multiply -1 by -2.
y-1=-x3+2
y-1=-x3+2
Step 5.1.2
Move all terms not containing y to the right side of the equation.
Step 5.1.2.1
Add 1 to both sides of the equation.
y=-x3+2+1
Step 5.1.2.2
Add 2 and 1.
y=-x3+3
y=-x3+3
y=-x3+3
Step 5.2
Reorder terms.
y=-(13x)+3
Step 5.3
Remove parentheses.
y=-13x+3
y=-13x+3
Step 6