Algebra Examples

Find the Perpendicular Line What is the equation of the line that is perpendicular to the line defined by the equation 2y=3x+7 and goes through the point (3,2) ?
What is the equation of the line that is perpendicular to the line defined by the equation 2y=3x+72y=3x+7 and goes through the point (3,2) ?
Step 1
Divide each term in 2y=3x+7 by 2 and simplify.
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Step 1.1
Divide each term in 2y=3x+7 by 2.
2y2=3x2+72
Step 1.2
Simplify the left side.
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Step 1.2.1
Cancel the common factor of 2.
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Step 1.2.1.1
Cancel the common factor.
2y2=3x2+72
Step 1.2.1.2
Divide y by 1.
y=3x2+72
y=3x2+72
y=3x2+72
y=3x2+72
Step 2
Find the slope when y=3x2+72.
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Step 2.1
Rewrite in slope-intercept form.
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Step 2.1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 2.1.2
Reorder terms.
y=32x+72
y=32x+72
Step 2.2
Using the slope-intercept form, the slope is 32.
m=32
m=32
Step 3
The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.
mperpendicular=-132
Step 4
Simplify -132 to find the slope of the perpendicular line.
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Step 4.1
Multiply the numerator by the reciprocal of the denominator.
mperpendicular=-(1(23))
Step 4.2
Multiply 23 by 1.
mperpendicular=-23
mperpendicular=-23
Step 5
Find the equation of the perpendicular line using the point-slope formula.
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Step 5.1
Use the slope -23 and a given point (3,2) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(2)=-23(x-(3))
Step 5.2
Simplify the equation and keep it in point-slope form.
y-2=-23(x-3)
y-2=-23(x-3)
Step 6
Write in y=mx+b form.
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Step 6.1
Solve for y.
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Step 6.1.1
Simplify -23(x-3).
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Step 6.1.1.1
Rewrite.
y-2=0+0-23(x-3)
Step 6.1.1.2
Simplify terms.
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Step 6.1.1.2.1
Apply the distributive property.
y-2=-23x-23-3
Step 6.1.1.2.2
Combine x and 23.
y-2=-x23-23-3
Step 6.1.1.2.3
Cancel the common factor of 3.
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Step 6.1.1.2.3.1
Move the leading negative in -23 into the numerator.
y-2=-x23+-23-3
Step 6.1.1.2.3.2
Factor 3 out of -3.
y-2=-x23+-23(3(-1))
Step 6.1.1.2.3.3
Cancel the common factor.
y-2=-x23+-23(3-1)
Step 6.1.1.2.3.4
Rewrite the expression.
y-2=-x23-2-1
y-2=-x23-2-1
Step 6.1.1.2.4
Multiply -2 by -1.
y-2=-x23+2
y-2=-x23+2
Step 6.1.1.3
Move 2 to the left of x.
y-2=-2x3+2
y-2=-2x3+2
Step 6.1.2
Move all terms not containing y to the right side of the equation.
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Step 6.1.2.1
Add 2 to both sides of the equation.
y=-2x3+2+2
Step 6.1.2.2
Add 2 and 2.
y=-2x3+4
y=-2x3+4
y=-2x3+4
Step 6.2
Reorder terms.
y=-(23x)+4
Step 6.3
Remove parentheses.
y=-23x+4
y=-23x+4
Step 7
image of graph
What is the equation of the line that is perpendicular to the line defined by the equation 2y=3x+7 and goes through the point (3,2)?
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