Algebra Examples

$y = x^{4} - x^{3} + x^{2} + x - 2$

Step 1

Set $x^{4} - x^{3} + x^{2} + x - 2$ equal to $0$ .

$x^{4} - x^{3} + x^{2} + x - 2 = 0$

Step 2

Solve for $x$ .

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Step 2.1

Factor the left side of the equation.

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Step 2.1.1

Regroup terms.

$x^{4} - x^{3} + x^{2} + x - 2 = 0$

Step 2.1.2

Factor $x^{3}$ out of $x^{4} - x^{3}$ .

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Step 2.1.2.1

Factor $x^{3}$ out of $x^{4}$ .

$x^{3} x - x^{3} + x^{2} + x - 2 = 0$

Step 2.1.2.2

Factor $x^{3}$ out of $- x^{3}$ .

$x^{3} x + x^{3} \cdot - 1 + x^{2} + x - 2 = 0$

Step 2.1.2.3

Factor $x^{3}$ out of $x^{3} x + x^{3} \cdot - 1$ .

$x^{3} (x - 1) + x^{2} + x - 2 = 0$

Step 2.1.3

Factor $x^{2} + x - 2$ using the AC method.

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Step 2.1.3.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 2$ and whose sum is $1$ .

$- 1, 2$

Step 2.1.3.2

Write the factored form using these integers.

$x^{3} (x - 1) + (x - 1) (x + 2) = 0$

Step 2.1.4

Factor $x - 1$ out of $x^{3} (x - 1) + (x - 1) (x + 2)$ .

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Step 2.1.4.1

Factor $x - 1$ out of $x^{3} (x - 1)$ .

$(x - 1) x^{3} + (x - 1) (x + 2) = 0$

Step 2.1.4.2

Factor $x - 1$ out of $(x - 1) x^{3} + (x - 1) (x + 2)$ .

$(x - 1) (x^{3} + x + 2) = 0$

Step 2.1.5

Factor.

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Step 2.1.5.1

Factor $x^{3} + x + 2$ using the rational roots test.

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Step 2.1.5.1.1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 2$

$q = \pm 1$

Step 2.1.5.1.2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 2$

Step 2.1.5.1.3

Substitute $- 1$ and simplify the expression. In this case, the expression is equal to $0$ so $- 1$ is a root of the polynomial.

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Step 2.1.5.1.3.1

Substitute $- 1$ into the polynomial.

${(- 1)}^{3} - 1 + 2$

Step 2.1.5.1.3.2

Raise $- 1$ to the power of $3$ .

$- 1 - 1 + 2$

Step 2.1.5.1.3.3

Subtract $1$ from $- 1$ .

$- 2 + 2$

Step 2.1.5.1.3.4

Add $- 2$ and $2$ .

$0$

Step 2.1.5.1.4

Since $- 1$ is a known root, divide the polynomial by $x + 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{x^{3} + x + 2}{x + 1}$

Step 2.1.5.1.5

Divide $x^{3} + x + 2$ by $x + 1$ .

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Step 2.1.5.1.5.1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$1$

$x^{3}$

$0 x^{2}$

$x$

$2$

Step 2.1.5.1.5.2

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x$ .

					$x^{2}$
	$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$

Step 2.1.5.1.5.3

Multiply the new quotient term by the divisor.

				$x^{2}$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			+	$x^{3}$	+	$x^{2}$

Step 2.1.5.1.5.4

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} + x^{2}$

				$x^{2}$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$

Step 2.1.5.1.5.5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$

Step 2.1.5.1.5.6

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$

Step 2.1.5.1.5.7

Divide the highest order term in the dividend $- x^{2}$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$x$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$

Step 2.1.5.1.5.8

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$x$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					-	$x^{2}$	-	$x$

Step 2.1.5.1.5.9

The expression needs to be subtracted from the dividend, so change all the signs in $- x^{2} - x$

				$x^{2}$	-	$x$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$

Step 2.1.5.1.5.10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$x$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$

Step 2.1.5.1.5.11

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	-	$x$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$	+	$2$

Step 2.1.5.1.5.12

Divide the highest order term in the dividend $2 x$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$x$	+	$2$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$	+	$2$

Step 2.1.5.1.5.13

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$x$	+	$2$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$	+	$2$
							+	$2 x$	+	$2$

Step 2.1.5.1.5.14

The expression needs to be subtracted from the dividend, so change all the signs in $2 x + 2$

				$x^{2}$	-	$x$	+	$2$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$	+	$2$
							-	$2 x$	-	$2$

Step 2.1.5.1.5.15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$x$	+	$2$
$x$	+	$1$		$x^{3}$	+	$0 x^{2}$	+	$x$	+	$2$
			-	$x^{3}$	-	$x^{2}$
					-	$x^{2}$	+	$x$
					+	$x^{2}$	+	$x$
							+	$2 x$	+	$2$
							-	$2 x$	-	$2$
										$0$

Step 2.1.5.1.5.16

Since the remander is $0$ , the final answer is the quotient.

$x^{2} - x + 2$

Step 2.1.5.1.6

Write $x^{3} + x + 2$ as a set of factors.

$(x - 1) ((x + 1) (x^{2} - x + 2)) = 0$

Step 2.1.5.2

Remove unnecessary parentheses.

$(x - 1) (x + 1) (x^{2} - x + 2) = 0$

Step 2.2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 1 = 0$

$x + 1 = 0$

$x^{2} - x + 2 = 0$

Step 2.3

Set $x - 1$ equal to $0$ and solve for $x$ .

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Step 2.3.1

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Step 2.3.2

Add $1$ to both sides of the equation.

$x = 1$

Step 2.4

Set $x + 1$ equal to $0$ and solve for $x$ .

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Step 2.4.1

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Step 2.4.2

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 2.5

Set $x^{2} - x + 2$ equal to $0$ and solve for $x$ .

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Step 2.5.1

Set $x^{2} - x + 2$ equal to $0$ .

$x^{2} - x + 2 = 0$

Step 2.5.2

Solve $x^{2} - x + 2 = 0$ for $x$ .

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Step 2.5.2.1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2.5.2.2

Substitute the values $a = 1$ , $b = - 1$ , and $c = 2$ into the quadratic formula and solve for $x$ .

$\frac{1 \pm \sqrt{{(- 1)}^{2} - 4 \cdot (1 \cdot 2)}}{2 \cdot 1}$

Step 2.5.2.3

Simplify.

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Step 2.5.2.3.1

Simplify the numerator.

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Step 2.5.2.3.1.1

Raise $- 1$ to the power of $2$ .

$x = \frac{1 \pm \sqrt{1 - 4 \cdot 1 \cdot 2}}{2 \cdot 1}$

Step 2.5.2.3.1.2

Multiply $- 4 \cdot 1 \cdot 2$ .

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Step 2.5.2.3.1.2.1

Multiply $- 4$ by $1$ .

$x = \frac{1 \pm \sqrt{1 - 4 \cdot 2}}{2 \cdot 1}$

Step 2.5.2.3.1.2.2

Multiply $- 4$ by $2$ .

$x = \frac{1 \pm \sqrt{1 - 8}}{2 \cdot 1}$

Step 2.5.2.3.1.3

Subtract $8$ from $1$ .

$x = \frac{1 \pm \sqrt{- 7}}{2 \cdot 1}$

Step 2.5.2.3.1.4

Rewrite $- 7$ as $- 1 (7)$ .

$x = \frac{1 \pm \sqrt{- 1 \cdot 7}}{2 \cdot 1}$

Step 2.5.2.3.1.5

Rewrite $\sqrt{- 1 (7)}$ as $\sqrt{- 1} \cdot \sqrt{7}$ .

$x = \frac{1 \pm \sqrt{- 1} \cdot \sqrt{7}}{2 \cdot 1}$

Step 2.5.2.3.1.6

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{1 \pm i \sqrt{7}}{2 \cdot 1}$

Step 2.5.2.3.2

Multiply $2$ by $1$ .

$x = \frac{1 \pm i \sqrt{7}}{2}$

Step 2.5.2.4

The final answer is the combination of both solutions.

$x = \frac{1 + i \sqrt{7}}{2}, \frac{1 - i \sqrt{7}}{2}$

Step 2.6

The final solution is all the values that make $(x - 1) (x + 1) (x^{2} - x + 2) = 0$ true.

$x = 1, - 1, \frac{1 + i \sqrt{7}}{2}, \frac{1 - i \sqrt{7}}{2}$

Step 3